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3 years ago

8

What’s the perimeter of this rectangle 2,5+D and 4-1,3D

1 answer:

koban [17]3 years ago

6 0

Answer:

The result can be shown in multiple forms.

Exact Form:

2,5+D,4-1,3D

Decimal form;

2,5+D,3,3D

Step-by-step explanation:

To find the perimeter of a rectangle, add the lengths of the rectangle's four sides. If you have only the width and the height, then you can easily find all four sides (two sides are each equal to the height and the other two sides are equal to the width). Multiply both the height and width by two and add the results.

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What is the prime factorization if 6400 using exponents

katovenus [111]

So prime factorization is as it seems, finding the prime factors for a number. With this number, break it down as such:

$\underbrace{6400}_{\underbrace{64}_{\underbrace{8}_{\underbrace{4}_{\boxed{2*2}} \boxed{2}}*\underbrace{8}_{\underbrace{4}_{\boxed{2*2}}\boxed{2}}}*\underbrace{100}_{\underbrace{10}_{\boxed{5*2}}*\underbrace{10}_{\boxed{5*2}}}}$

<u>Looking at our factors, the prime factorization of 6400 is $2^8*5^2$ </u>

5 0

3 years ago

Please help ill mark brilliant

Anastasy [175]

B is the answer to the question :)

8 0

3 years ago

Read 2 more answers

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago

Write an expression that represents the quantity 5 more than a number

Natali5045456 [20]

6+7 is that good i hope so

3 0

2 years ago

I have to add then put the answer in simplest form and the fraction is 5/8 plus 3/10

tamaranim1 [39]

Answer:

37/40

Step-by-step explanation:

5 0

3 years ago