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podryga [215]
3 years ago
13

Point A is at (3, 2.6) and point B is at (3, 1.4) on a coordinate grid. The distance between the two points is ____. Input numbe

rs and decimal point only, such as 5.8.
Mathematics
2 answers:
IgorLugansk [536]3 years ago
5 0
1.2 I hope this helps you
Wewaii [24]3 years ago
3 0
The answer to your problem is 1.2.
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Simplify ( 1/2A + 1/2B )^2
zysi [14]
Notice that both A and B are multiplied by (1/2).

Thus, the given expression can be re-written as [(1/2)(A+B)]^2.

Square the (1/2) and the (A+B) separately, and then multiply together the resulting squares:

(1/4)(A^2 + 2AB + B^2)

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME!! I WILL GIVE U BRAINLIEST
Anvisha [2.4K]

Answer:

Step-by-step explanation:the anwser is the middle one

5 0
3 years ago
Triangle ABC has vertices at A(2,3),B(-4,-3) and C(2,-3) find the coordinates of each point of concurrency.
dem82 [27]

Answer:

Circumcenter =(-1,0)

Orthocenter =(2,-3)

Step-by-step explanation:  

Given : Points A = (2,3), B = (-4,-3), C = (2,-3)  

Formula used :  

→Mid point of two points- (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

→Slope of two points - \frac{y_2-y_1}{x_2-x_1})

→Perpendicular of a line = \frac{-1}{slope of line})

Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = -1  

Equation of AB with slope -1 and the coordinates (-1,0) is,  

(y – 0) = -1(x – (-1))  

y+x=-1………………(1)  

Similarly, for AC  

Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

Equation of AC with slope 0 and the coordinates (2,0) is,  

(y – 0) = 0(x – 2)  

y=0 ………………(2)  

By solving equation (1) and (2),  

put y=0 in equation (1)

y+x=-1

0+x=-1

⇒x=-1  

So the circumcenter(P)= (-1,0)

To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))  

y+3=0

y=-3………………(4)  

Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


7 0
3 years ago
Can you so me work for7\10-1\2
Rina8888 [55]
Well, 1/2 is equal to 5/10... so 7/10 - 5/10 is 2/10 because 7-5=2 :)
5 0
3 years ago
Read 2 more answers
5x-2y=30 complete the missing value in the solution to the question (8, )
natali 33 [55]

Answer:

(8,5)

Step-by-step explanation:

5x-2y=30

lets substitute "8" as x and see where that takes us

5(8)-2y=30

40-2y=30

subtract 40 on both sides

-2y=-10

divide by "-2" on both sides

y=5

(8,5) is your answer

4 0
3 years ago
Read 2 more answers
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