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vitfil [10]
3 years ago
5

If (2 − 3i) + (x + yi) = 6, what is x + yi?

Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0

(2 − 3i) + (x + yi) = 6

We add the left hand side

(2+x) + (-3+y)i = 6

6 can be written in a+ib

6 can be written as 6 + 0i

(2+x) + (-3+y)i = 6 +0i

Now we frame 2 equations

2 + x= 6

-3 + y =0

Solve the first equation

2 + x = 6

Subtract 2 from both sides

x = 4

solve the second equation

-3 + y =0

Add 3 on both sides

y= 3

So x+yi is 4+3i

nexus9112 [7]3 years ago
3 0

Answer:

x + yi = 4 + 3i

Step-by-step explanation:

Equation:

(2 − 3i) + (x + yi) = 6

Simple solution:

(2 − 3i) + (x + yi) = 6

= (2 − 3i) + (x + yi) - (2 − 3i) = 6 - (2 − 3i)

=  x + yi = 6 - 2 +3i

=  x + yi = 4 + 3i

                                                               =  x + yi = 4 + 3i

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Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8
Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21

Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5
6 0
3 years ago
Help me plzzz i need hwlp
Anuta_ua [19.1K]

Answer:

x = -2

Step-by-step explanation:

so how i would do it is

-4x + (-3) = -x +3 you would subtract 3 from the right side and add/ subtract it onto the left

then you have

-4x + (-6) = -x next you take the -4x and you would add it to the right side to get

-6 = 3x

lastly you divide -6 / 3 to get

x = -2

would love if i could have brainlist

3 0
3 years ago
Can I get help on this please? I think the answer might be (A) but i'm not sure.
Alex Ar [27]
Yeah it would be A. because x approaching infinity is to the right of the graph, and since there is a horizontal asymptote at -3 then its correct

4 0
3 years ago
How many miles did Daria walk in all ?
Alexxx [7]

Answer:

3 and 7/10

Step-by-step explanation: convert how much daria walked in the morning to a denominator of 10 and then add

8 0
3 years ago
Lee is thinking of 2 numbers, the product is 18.the quotient is 2. what are yhe two numbers?
jeka94
xy=18\\
\dfrac{x}{y}=2\\\\
xy=18\\
x=2y\\\\
2y\cdot y=18\\
2y^2=18\\
y^2=9\\
y=-3 \vee y=3\\\\
x=2\cdot (-3) \vee x=2\cdot 3\\
x=-6 \vee x=6\\\\
\boxed{(x,y)=\{(-6,-3),(6,3)\}}
4 0
4 years ago
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