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4 years ago

PLS ANSWER NOW i'm desperate

Mathematics

1 answer:

IceJOKER [234]4 years ago

8 0

Answer:

1.6 < x < 9.6

Step-by-step explanation:

The smallest the third side can be is greater than the difference of the other two sides

x > 5.6 -4

x > 1.6

The largest the third side can be is less than the sum of the other two sides

x < 5.6 +4

x < 9.6

1.6 < x < 9.6

You might be interested in

20% of what number is 6.5?

scoundrel [369]

Answer:

1.3

Step-by-step explanation:

20/100 x 6 5/10 =

1 3/10

Hopes this helps

3 0

3 years ago

List the single-digit divisors of 2100. I really need help

liberstina [14]

Answer:

1, 2, 3, 4, 5, 6, 7

Step-by-step explanation:

Prime factors of 2100 are:

2100 = 2*2*3*5*5*7

The single-digit divisors are:

1, 2, 3, 2*2= 4, 5, 2*3= 6, 7

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Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:

2100/1 = 2100, yes
2100/2 = 1050, yes
2100/3 = 700, yes
2100/4 = 525, yes
2100/5 = 420, yes
2100/6 = 350, yes
2100/7 = 300, yes
2100/8 = 262.5, no
2100/9 = 233.33, no

So all the numbers from 1 to 7

5 0

3 years ago

Please answer this question asap

lukranit [14]

Answer:

Use the formula

P(X,y) ___y=x__(Reflection)_____P'(y,x)

I think it will help you.

8 0

3 years ago

Ed & Heath won the grand

mestny [16]

Answer:

224

Step-by-step explanation:

(100+12)*2

6 0

3 years ago

One of our brainliest, Konrad509, made this:

Reil [10]

$\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x$

A=10, B=11, C=12, etc.

$\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2$

$121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0$

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that $x\in\mathbb{N}$ . Moreover we can deduce that $x\geq19$ since there is $J$ and $J=19$ .

After you succesfully solve it, you should get the answer $x=20$ .

7 0

4 years ago