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3 years ago

7

If you were to solve this inequality, do you need to flip the Inequality symbol?

2 answers:

Pavlova-9 [17]3 years ago

8 0

Answer: no

I would not flip the inequality symbol

Elza [17]3 years ago

3 0

Answer:

I think fractions are smaller than whole numbers

So I think No (viewpoint)

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Shirley spelled 12 of her 16 spelling words correctly on the test. What percent grade did shirley get on the test

Black_prince [1.1K]

Answer:

75%

Step-by-step explanation:

percent = part/whole * 100%

percent = 12/16 * 100%

percent = 0.75 * 100%

percent = 75%

Answer: 75%

5 0

3 years ago

Solve the equation <br> 1/6(12z-18)=2z-3

Romashka-Z-Leto [24]

1/6(12z-18)=2z-3

12/6z-18/6 =2z-3

2z-3=2z-3

there are infinite solutions for this equation or all real numbers

8 0

3 years ago

10. A bin of books at a bookstore had a 60% markdown off the original price and also offered a 35% coupon to the first 200 custo

valkas [14]

Answer:

300%

Step-by-step explanation:

bc i know

6 0

3 years ago

Read 2 more answers

Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0

3 years ago

Using the Multiplication Property of -1

Papessa [141]

A. -(a+5)

Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:

-(a+5) * -1 = a+5

B. -(-x+31)

Apply the distributive property:

-(-x+31) becomes (- -x +31) which simplifies to (x+31)

multiply that by -1 to get -x+31

C. -(4x+12)

Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:

-(4x+12) * -1 = 4x+12

7 0

3 years ago