3 years ago

The base of an isosceles tiangle has a length of 25. what can you say about the lengths of the legs?

1 answer:

7 0

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side (or else, it can't be a closed polygon). Since we know that the two sides in question are both of the same length in this case (since the triangle isosceles), their individual lengths must be greater than 25/2 = 12.5.

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3 years ago

Please help with number 10

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Answer:

see below for a drawing
the area of one of the trapezoids is 20 units²

Step-by-step explanation:

No direction or other information about the desired parallelogram is given here, so we drew one arbitrarily. Likewise for the segment cutting it in half. It is convenient to have the bases of the trapezoids be the sides of the parallelogram that are 5 units apart.

The area of one trapezoid is ...

A = (1/2)(b1 +b2)h = (1/2)(3+5)·5 = 20 . . . . square units

The sum of the trapezoid base lengths is necessarily the length of the base of the parallelogram, so the area of the trapezoid is necessarily 1/2 the area of the parallelogram. (The area is necessarily half the area of the parallelogram also because the problem has us divide the parallelogram into two identical parts.)