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4 years ago

The base of an isosceles tiangle has a length of 25. what can you say about the lengths of the legs?

1 answer:

7 0

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side (or else, it can't be a closed polygon). Since we know that the two sides in question are both of the same length in this case (since the triangle isosceles), their individual lengths must be greater than 25/2 = 12.5.

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How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

3 years ago

Of a group of students 5/8 of them are boys. The girls are put into groups so that each group has 1/6 of the total number of stu

Marina86 [1]

I believe the answer is 9.

3 0

3 years ago

A bag has 4 red marbles, 5 blue marbles, and 6 green marbles. What is the probability if choosing a red marble from the bag, not

raketka [301]

Answer: 4/35

Step-by-step explanation:

Number of red marbles = 4

Number of blue marbles = 5

Number of green marbles = 6

Total number of marbles = 4+5+6 = 15

When a red marble is picked, the probability is 4/15, then to pick a green marble after that, we have 14 marbles left and probability of picking green is 6/14.

Now, probability of choosing a red marble from the bag, not putting it back, and then choosing a green marble will be:

= 4/15 × 6/14

= 24/210

= 4/35

6 0

3 years ago

How do you solve the following equation : X/-3 + 2=4

goblinko [34]

Answer:

For this equation you be inverse operation giving you the answer -6

further information down below :)

Step-by-step explanation:

Your goal for this is to isolate the variable which is x.

First, find the operation opposite of addition which is subtraction

When you add that operation to both sides with the constant(2)

2 and 2 cancel each other out, but to the for the term(4) 4-2=2

after that you have your new term which is x/-3=2

You do the same thing but to in division because the opposite of multiplication is division in this case you multiply -3 to both sides -3*-3 cancel each other out, now you have-3*2= negative times a positive equal negative in anyway so, overall you get -6.

To check:

you do the full equation now that you have isolated the variable, you now can do the operations normally which are. -6/-3=2 because when you divide a negative by a negative you get a positive end out with 2+2=4 which is correct and match the sum.

This means that our answer is correct :)

5 0

3 years ago

I need help on the 3 of them

Tamiku [17]

Answer:

1) 75 minutes / 1hour 15minutes

Step-by-step explanation:

to get one question done takes (45 ÷ 12) minutes. then times by 20.

Answer

2) I'm not too sure, I got 208.3 reoccurring, but that doesn't seem right so sorry if it's wrong

Answer

3)168 girls

step-by-step explanation

364 ÷ (6+7) × 6

6 0

3 years ago