Ok so the lines with two triangles are parralel to eachother. The lines with one are parallel to eachother.
The angle of 109° and angle of z° equal eachother. Z=109°
Since 109°, 33° and y° form a triangle, the sum of the angles will equal 180. Add 109 and 33 to get 142. Subtract 142 from 180 to get y°=38°.
Since z=109, this means that the triangle is congruent with the other. Since the congruent triangles are in a rhombus, then the angles are flipped. Thus, angle x =33°.
z=109°
y=38°
x=33°
Step-by-step explanation:
sinx = a/b
tanx= a/c
cosx= c/b
Answer:
f(4f + 1)
Step-by-step explanation:
Given
4f² + f ← factor out f from each term
= f(4f + 1)
Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
If R is the midpoint of PS, then PR = RS -- (1)
Also, PR + RS = PS -- (2)
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PR + RS = PS
7x + 23 + 13x - 19 = PS
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Now, PR = PS
7x + 23 = 13x - 19
7x - 13x = -19 - 23
-6x = -42
x = -42/-6
x = 7
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PS = 7x + 23 + 13x - 19
PS = 7(7) + 23 + 13(7) - 19
PS = 49 + 23 + 91 - 19
<u>PS </u><u>=</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u>
Hope it helps!
꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂
