Area of 1 exam room = 10 ft. × 10 ft. = 100 ft.²
Area of 10 exam room = 100 ft.² × 10 = 1000 ft.²
Area of waiting room = 20 ft. × 15 ft. = 300 ft.²
Area of office area = 25 ft. × 20 ft. = 500 ft.²
Now,
Total area of the hospital to be replaced = 1000 ft.² + 300 ft.² + 500 ft.² = 1800 ft.²
Answer:
Abcissa = X, and Ordinate = Y
(-7,-2)
Is the answer
f ( 7 ) = 2.4 ft
Step-by-step explanation:
Solution:-
- This is modeled using a geometric sequence function with initial height from which ball is dropped hi = 18 feet, and a decrease in height by 25% after each successive bounce :
f ( x ) = 18 (0.75)^x
Where, x e [ 0 , ∞ ) : The number of bounces.
f (x) : The maximum height after xth bounce.
- The maximum height reached by the ball after its 7th bounce. So, x = 7:
f ( 7 ) = 18 (0.75)^7
f ( 7 ) = 2.4027 ft
- To the nearest tenth:
f ( 7 ) = 2.4 ft
Answer:
9 textbooks!
Step-by-step explanation:
Rucksack can hold = 6kg
Mass of textbook = 680g
So, here we need to show the division for finding the number of textbooks it can hold.
680 g in KG's = 0.68
Now, 6/0.68
That is 8.82 ( Round off = 9 textbooks)
