-5.5a-9.35+39.78-59.28a<-14.916
-64.78a+30.43<-14.916
-30.43<-30.43
-64.78a<-45.346
a>0.7
Since , the relation is linear .
Let equation is y = mx + c .
Putting , x = 0 and y = 32 .
32 = c .......( 1 )
Also , putting x = 100 and y = 212 .
We get :
212 = 100m + c .......( 2 )
Comparing equation 1 and 2 .
100m = 212 - 32
x = 1.8
Therefore , y = 1.8x + 32 .
Hence , this is the required solution .
Let them be X and Y..
now...
yx=100 ....
y=100/y ...
now...
x+y= s....where s is their sum...
but y=100/x
now....x+100/x=s..
by differentiating both sides with respect to x..
1-100/x^2=ds/dx
but ds/dx=0..
100=x^2 ..
x=10..
so y=10
Answer:
c
Step-by-step explanation:
answer is c on edge
Just do 4x5 then add the zeros
