Answer:
Yes.
2 feet
Step-by-step explanation:
Pieces of copper that Arsenio needs in total = 27 pieces
Length of each piece of copper tubing that he needs = 2/9 foot
Length of available tubing = 8 foot
Since, the length of each piece is 2/9 foot, the length of 27 pieces would be:
![\frac{2}{9} \times 27 = 6](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7D%20%5Ctimes%2027%20%3D%206)
This means, Arsenio needs 6 feet in total for the copper tubing. Since he got 8 feet in total, he has sufficient amount of tubing available.
After making the 27 pieces, he will be left with 8 - 6 = 2 feet of tubing.
Answer:
![a_n = 16(\frac{1}{4})^{n - 1}](https://tex.z-dn.net/?f=%20a_n%20%3D%2016%28%5Cfrac%7B1%7D%7B4%7D%29%5E%7Bn%20-%201%7D%20)
Step-by-step explanation:
Given:
Fifth term of a geometric sequence = ![\frac{1}{16}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B16%7D%20)
Common ratio (r) = ¼
Required:
Formula for the nth term of the geometric sequence
Solution:
Step 1: find the first term of the sequence
Formula for nth term of a geometric sequence =
, where:
a = first term
r = common ratio = ¼
Thus, we are given the 5th term to be ¹/16, so n here = 5.
Input all these values into the formula to find a, the first term.
![\frac{1}{16} = a*\frac{1}{4}^{5 - 1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B16%7D%20%3D%20a%2A%5Cfrac%7B1%7D%7B4%7D%5E%7B5%20-%201%7D%20)
![\frac{1}{16} = a*\frac{1}{4}^{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B16%7D%20%3D%20a%2A%5Cfrac%7B1%7D%7B4%7D%5E%7B4%7D%20)
![\frac{1}{16} = a*\frac{1}{256}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B16%7D%20%3D%20a%2A%5Cfrac%7B1%7D%7B256%7D%20)
![\frac{1}{16} = \frac{a}{256}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B16%7D%20%3D%20%5Cfrac%7Ba%7D%7B256%7D%20)
Cross multiply
![1*256 = a*16](https://tex.z-dn.net/?f=%201%2A256%20%3D%20a%2A16%20)
Divide both sides by 16
![\frac{256}{16} = \frac{16a}{16}](https://tex.z-dn.net/?f=%20%5Cfrac%7B256%7D%7B16%7D%20%3D%20%5Cfrac%7B16a%7D%7B16%7D%20)
![16 = a](https://tex.z-dn.net/?f=%2016%20%3D%20a%20)
![a = 16](https://tex.z-dn.net/?f=%20a%20%3D%2016%20)
Step 2: input the value of a and r to find the nth term formula of the sequence
nth term = ![ar^{n - 1}](https://tex.z-dn.net/?f=%20ar%5E%7Bn%20-%201%7D%20)
nth term = ![16*\frac{1}{4}^{n - 1}](https://tex.z-dn.net/?f=%2016%2A%5Cfrac%7B1%7D%7B4%7D%5E%7Bn%20-%201%7D%20)
![a_n = 16(\frac{1}{4})^{n - 1}](https://tex.z-dn.net/?f=%20a_n%20%3D%2016%28%5Cfrac%7B1%7D%7B4%7D%29%5E%7Bn%20-%201%7D%20)
Option A: >
Solution:
Given a triangle GHJ.
The line GH is perpendicular to line HJ.
This means the triangle is a right angled triangle.
In ΔGHJ, GH is the base of the triangle and
HJ is a height of the triangle.
Then the third side must be the hypotenuse of the right triangle.
We know that by the Pythagoras theorem,
![(\text {Hypotenuse})^2=(\text{Base})^2+(\text{Height})^2](https://tex.z-dn.net/?f=%28%5Ctext%20%7BHypotenuse%7D%29%5E2%3D%28%5Ctext%7BBase%7D%29%5E2%2B%28%5Ctext%7BHeight%7D%29%5E2)
![(\text {GJ})^2=(\text {GH})^2+(\text {HJ})^2](https://tex.z-dn.net/?f=%28%5Ctext%20%7BGJ%7D%29%5E2%3D%28%5Ctext%20%7BGH%7D%29%5E2%2B%28%5Ctext%20%7BHJ%7D%29%5E2)
This clearly shows that the hypotenuse is greater than the height.
⇒ GJ > HJ
Option A: > is the correct answer.
If line GH is perpendicular to line HJ, then GJ is > HJ.
1... the wording is a little confusing.
Is the charge $0.18 per mile or is it actually $36.18 per mile?