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nevsk [136]
4 years ago
5

Rosy has 16 pencils and 24 erasers. She is putting together packets that will havean equal number of pencils and erasers in each

packet. If Rosy uses all of the pencils and erasers, what is the maximum number of packets she can make?
Mathematics
2 answers:
N76 [4]4 years ago
5 0
16 = 2^4

24 = 2^3 \times 3

\text{HCF =}2^3 = 8

Maximum number of packets = 8

16 ÷ 8 = 2
There are 2 pencils in each packet.

24÷8 = 3
There are 3 erasers in each bag.

Rosy can have a maximum of 8 packets. Each packet has 2 pencils and 3 erasers.
Evgesh-ka [11]4 years ago
4 0

Answer:

If she puts 2 pencils and 3 erasers in each packet,

Rosy can make a total of 8 packets.

Step-by-step explanation:

I hope this helps you!

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Step-by-step explanation:

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2 years ago
Combine the radicals 4V7 +3V28​
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Answer:

The answer is

<h2>10 \sqrt{7}</h2>

Step-by-step explanation:

To solve the radicals make sure that they both have the same radical

That's

<h3>4 \sqrt{7}  + 3 \sqrt{28}</h3>

Simplify 3√28 in order to combine the radicals

We have

<h3>3 \sqrt{4 \times 7}  = 3 \times  \sqrt{4}  \times  \sqrt{7}</h3><h3>= 3 \times 2 \times  \sqrt{7}</h3><h3>= 6 \sqrt{7}</h3>

So we now have

<h3>4 \sqrt{7}  + 6 \sqrt{7}</h3>

Using the rules of surds

That's

<h3>x \sqrt{a }  + y \sqrt{a}  = (x + y) \sqrt{a}</h3>

Simplify the expression

We have

<h3>4 \sqrt{7}  + 6 \sqrt{7 }  = (4 + 6) \sqrt{7}</h3>

We have the final answer as

<h3>10 \sqrt{7}</h3>

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