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Alona [7]
3 years ago
11

A can of juice has a radius of 3 inches and a height of 6 inches. What is the volume of the can?

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

169.95

Step-by-step explanation:

Use formula Pi×r²

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Is y= 2x cubed +6 linear or non-linear
zhuklara [117]
Non linear because nothing cubed or squared can be linear.
Hope this helps
6 0
3 years ago
Find the exact value of cos(arcsin(1/4)). For full credit, explain your reasoning.
Westkost [7]
First way
arcsin(1/4) means that 1/4 sin of the angle.

sin(α)=1/4
sin²α+cos²α=1
(1/4)²+cos²α=1
cos²α=1-1/16 =15/16
cosα=+/-(√15)/4

<span>Second way
</span>
sin(α)=1/4 =opposite leg/hipotenuse
cos(α)=adjacent leg/hypothenuse
adjacent leg =√(hypotenuse²- Opposite²)=√(16-1)=√15
cosα=+/-√15/4

For one value of sinα, possible 2 values of cosα.

5 0
2 years ago
5/6 x 12 in simplest form?
Jlenok [28]

Answer:

10

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging
kirza4 [7]

Answer:

Step-by-step explanation:

given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging

Clerk          I           II           III    total

   

Pack      0.33          0.23    0.44 1

   

Defective 0.02 0.025    0.015  

   

Pack&def 0.0066 0.00575 0.0066 0.01895

a)  probability that a randomly selected box of chocolates was packed by Clerk 2 and does not contain any defective chocolate

= P(II clerk) -P(II clerk and defective) = 0.23-0.00575=0.22425

b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)

=0.01895

c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3

=P(clerk 3 and def)/P(defective)

=\frac{0.0066}{0.01895} \\=0.348285

8 0
3 years ago
A 99% confidence interval for the mean μ of a population is computed from a random sample and found to be 6 ± 3. We may conclude
valentina_108 [34]

Answer:

A. there is a 99% probability that μ is between 3 and 9.

Step-by-step explanation:

From a random sample, we build a confidence interval, with a confidence level of x%.

The interpretation is that we are x% sure that the interval contains the true mean of the population.

In this problem:

99% confidence interval.

6 ± 3.

So between 6-3 = 3 and 6 + 3 = 9.

So we are 99% sure that the true population mean is between 3 and 9.

So the correct answer is:

A. there is a 99% probability that μ is between 3 and 9.

4 0
3 years ago
Read 2 more answers
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