Answer:
b,c and d
Explanation:
The following processes are coupled to the dephosphorylation of ATP
b. the endergonic reaction forming gluco-6-phosphate
c. Myosin action during muscle contraction
d. de novo anabolism of nucleotide
Ka is known as the acid dissociation constant. It is a measure of an acid strength of a solution. It is an equilibrium constant for the dissociation of an acid or base in a solvent. A very large value of Ka represents a strong acid. For instance, for HI, Ka is 3.2 x 10^9 and for HBr, Ka is 1.0 *10^9.
A hot touch means that heat is leaving the system, so the answer is C. exothermic
A gas at STP is heated to 35 degree C. The new pressure will be 2.41 atm.
<h3>What is Gay-Lussac law?</h3>
The pressure of the mass of the gas is directly proportional; to the temperature of the gas.
![\dfrac{P_1 }{T_1} =\dfrac{P_2}{T_2}](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1%20%7D%7BT_1%7D%20%20%3D%5Cdfrac%7BP_2%7D%7BT_2%7D)
Converting the temperature into kelvin
The initial temperature = 35 °C = 35 + 273 K= 308 K
The final temperature = 50 °C =50 + 273 K = 323 K
Initial pressure = 2.3 atm
Final pressure ?
Putting the values in the equation
![\dfrac{P_1 }{T_1} =\dfrac{P_2}{T_2}\\\\\\{P_2 = \dfrac{P_1 \times T_2}{T_1} \\\\\\\\\\{P_2 = \dfrac{2.3 \times 323 }{308} = 2.41 atm.](https://tex.z-dn.net/?f=%5Cdfrac%7BP_1%20%7D%7BT_1%7D%20%20%3D%5Cdfrac%7BP_2%7D%7BT_2%7D%5C%5C%5C%5C%5C%5C%7BP_2%20%3D%20%5Cdfrac%7BP_1%20%5Ctimes%20T_2%7D%7BT_1%7D%20%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%7BP_2%20%3D%20%5Cdfrac%7B2.3%20%5Ctimes%20323%20%7D%7B308%7D%20%3D%202.41%20atm.)
Thus, the new pressure will be 2.41 atm.
Learn more about Gay-Lussac law
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Answer:
15.17 g
Explanation:
To answer this, we need to find the molar mass of nickel in nickel (II) fluoride. The formula for nickel (II) fluoride is NiF2. This gives us the molar mass of 96.69 g. The mass percentage of nickel is 60.70% approximately (as we divide the molar mass of nickel by that of nickel (II) fluoride), and 60% of 25g gives us 15.17 g