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AysviL [449]
3 years ago
6

Which of the following organisms would likely be found on a decaying deer carcass (dead deer)?

Chemistry
2 answers:
saw5 [17]3 years ago
6 0

Answer:

c. Bacteria and fungus

Explanation:

This would likely be found on a decaying deer carcass

TEA [102]3 years ago
3 0

Answer:

c. bacteria and fungus

Explanation:

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What is the standard enthalphy change ΔHo, for the reaction represented above? (ΔHof of C2H2(g) is 230 kJ mol-1; (ΔHof of C6H6(g
wolverine [178]

Answer:

-608KJ/mol

Explanation:

3 C2H2(g) -> C6H6(g)

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= ΔHC6H6 - 3ΔHC2H2

ΔHrxn = 83 - 3(230)

ΔHrxn = -608

6 0
3 years ago
If you were going to graphically determine the enthalpy of vaporization, δhvap, for this liquid, what points would you plot
Klio2033 [76]
It depends on what type of graph you have. The easiest would be using a H-T diagram. Enthalpy of vaporization is the physical change from liquid to vapor. It occurs at a constant pressure and a constant temperature. As shown in the picture, 1 point is drawn on the subcooled liquid, and another point of the saturated vapor isothermal line. Now, the difference between those two points is the value for the enthalpy of vaporization of water.

8 0
3 years ago
Which of the following compounds is not possible?
neonofarm [45]

Answer:

C

Explanation:

Large chlorine atoms can not fit within the atoms of boron

4 0
3 years ago
A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law
zysi [14]

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

    \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

 V₁ is the initial volume

 T₁ is the initial temperature

 V₂ is the final volume

 T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

   V₂ = \frac{V_{1} }{T_{1} }  x T_{2}  = \frac{547}{331 }  x 376

 V₂ =  621.4L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

3 0
3 years ago
Read 2 more answers
A quantity of 1.922 g of methanol (CH3OH) was burned in a constant-volume bomb calorimeter. Consequently, the temperature rose b
dezoksy [38]

Answer:

872.28 kJ/mol

Explanation:

The heat released is:

ΔH = C*ΔT

where ΔH is the heat of combustion, C is the heat capacity of the bomb plus water, and ΔT is the rise of temperature. Replacing with data:

ΔH =  9.47*5.72 = 54.1684kJ

A quantity of 1.922 g of methanol in moles are:

moles = mass / molar mass

moles = 1.992/32.04 = 0.0621 mol

Then the molar heat of combustion of methanol is:

ΔH/moles = 54.1684/0.0621 = 872.28 kJ/mol

5 0
3 years ago
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