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nexus9112 [7]
3 years ago
12

Simplify each exponential expression using the properties of exponents and match it to the correct answer

Mathematics
2 answers:
jekas [21]3 years ago
7 0

3^-3*2^-3*6^3 = 1

last one=2

2nd one =1/2

mr_godi [17]3 years ago
6 0

3^-3 * 2^-3 *6^3 / (4^0)^2

= 6^-3 * 6^3 / (1)^2

= 1 / 1

= 1

---------------------------------------

2^4 * 3^5 / (2*3)^5

= 2^4 * 3^5 / 2^5 *3^5

= 1/ 2^1

= 1/2

---------------------------

(3 * 2)^4 * 3^-3 / 2^3 * 3

=3^4 * 2^4 * 3^-3 / 2^3 * 3

= 3^1 * 2^4 / 2^3 * 3

= 2^1

= 2

-----------------------

3^2 * 4^3 * 2^-1 / (3 * 4)^2

= 3^2 * 4^3 / 3^2 * 4^2 * 2^1

= 4^1 / 2^1

= 4/2

= 2

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????????????????vbzjjzjdvdu
Romashka-Z-Leto [24]

Answer:

A

Step-by-step explanation:

There is an empty dot on 4, meaning b is not equal to 4.

The arrow is going to the left of 4, so it means that b is less that four.

Hope that helps!

3 0
2 years ago
Read 2 more answers
A store has a 25\%25% off sale on coats. With this discount, the price of one coat is \$34.50$34.50. What is the original price
timama [110]

Answer:

$46

Step-by-step explanation:

A percent is a portion of 100. If  we receive 25% off then we pay 75% of the price. 100%-25%=75%. $34.50 is 75% of the original price. We find the new price through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio of $ to $.

\frac{75}{100} =\frac{34.50}{y}

I can now cross-multiply by multiplying numerator and denominator from each ratio.

75y=100(34.50)\\75y=3450

I now solve for y by dividing by 75.

\frac{75y}{75} =\frac{3450}{75} \\y= 46....

The original price was $46.


5 0
3 years ago
PLEASE HELP ITS MATH THANK YOUUUU
NISA [10]
Answer: 10 meters

Explanation:

29 cm : blank meters

So how do we get from 348 cm to 29 cm?

To figure this out we divide.

348 divided by 28 = 12

we divided by 12 so we do the same with 120

120 divided by 12 = 10

So that’s the answer.

I hope this makes sense and helps you :)
6 0
2 years ago
For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\
kkurt [141]
An inverse function is a function that reverses another function, so we have a function called:

p(x)

Then, the inverse function will be as follows:

p^{-1}(x)

Given that y = p(x), we need to isolate x in terms of y:

y =  x^{2} -9
∴ y+9 = x^{2}

So:

x=+\sqrt{y+9} and x=-\sqrt{y+9}

therefore, exchanging variables x and y:

y=+\sqrt{x+9} and y=-\sqrt{x+9}
p^{-1}(x)=+\sqrt{x+9} and p^{-1}(x)=-\sqrt{x+9}

Which are the figures shown below.

7 0
3 years ago
Pls help me !!!!!!!!!!!!!!!!!!!!!!!!
Vikentia [17]

Answer:

9.89 m

Step-by-step explanation:

AC is the hypotenuse (H)

x is the opposite (O)

O and H are in sine

sin=O/H

H=O/sin

H=7.9/sin(53)

=9.89187169943418

3 SF

9.89 m

8 0
3 years ago
Read 2 more answers
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