If 6 and 12 are 2 positive number then there should be 2 for each one of them
Leading coefficient = -3
Constant = 2
When you order them in standard form, you need to put them in ascending order of the exponents. Therefore the -3x^2 would come first, which makes the number attached (-3) the lead coefficient.
Also, since the number (2) without an x attached would be last (due to the power of x technically being 0), than that is the constant.
The region(s) represent the intersection of Set A and Set B (A∩B) is region II
<h3>How to determine which region(s) represent the intersection of Set A and Set B (A∩B)?</h3>
The complete question is added as an attachment
The universal set is given as:
Set U
While the subsets are:
The intersection of set A and set B is the region that is common in set A and set B
From the attached figure, we have the region that is common in set A and set B to be region II
This means that
The intersection of set A and set B is the region II
Hence, the region(s) represent the intersection of Set A and Set B (A∩B) is region II
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Answer:
<h2>Kelly is wrong, with this congruent parts, we can conclude that triangles are congruent.</h2>
Step-by-step explanation:
To demonstrate congruent triangles, we need to use the proper postulates. There are at least 5 postulates we can use.
- Angle-Angle-Side Theorem (AAS theorem).
- Hypotenuse-Leg Theorem (HL theorem).
- Side-Side-Side Postulate (SSS postulate).
- Angle-Side-Angle Postulate (ASA postulate).
- Side-Angle-Side Postulate (SAS postulate).
In this case, Kelly SAS postulate, because the corresponding sides-angles-sides are congruent, i.e., KL ≅ MN and LM ≅ KN, also, all corresponding angles are congruent.
So, as you can see, only using SAS postulate, the congruency can be demonstrated. (Refer to the image attached to see an example of SAS postulate)