Let's find the slope for line t first.
We can use the given points 2,6 and 10,1 to find the slope using the slope formula.
1 - 6 / 10 - 2
-5/8
The slope is -5/8.
Because we know the slope of this line, we can find the slope of the next line instantly, as they are perpendicular.
When a slope is perpendicular to another, it is equal to the negative reciprocal.
Negative reciprocal of -5/8 = 8/5
<h3>The slope of line u is 8/5</h3>The outlier of a dataset is a data element that is relatively far from the remaining data elements
<u>(a) Prove that 99 is an outlier for Pet</u>
We have:
<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>
The quartiles positions are:
So, we have:
From the pet group:
The data elements at the 4th and 12th positions are 68 and 79
So, we have:
The lower and upper limits of the outlier are:
So, we have:
This means that data below 51.5 or above 95.5 are outliers.
<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>
<u>(b) The parallel box plot</u>
The three groups are:
<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>
<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>
<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>
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See attachment for the parallel box plots
Read more about box plots and outliers at:
