Question

Solve inequality √(2−x) < x.

Answer 1

$[tex]\sqrt{2-x}0\\ x^2+2x-x-2>0\\ x(x+2)-1(x+2)>0\\ (x-1)(x+2)>0\\ x\in(-\infty,-2)\cup(1,\infty)\\\\ \boxed{x\in(-\infty,-2)\cup(1,2\rangle}$[/tex]