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Drupady [299]
4 years ago
8

What is the x value ?????

Mathematics
1 answer:
Lady bird [3.3K]4 years ago
3 0
I got x=2.64 or x=1.32 i don't know if i done it right 
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Verify the identity. <br><br> tan x plus pi divided by two = -cot x
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Recall that sin(π/2) = 1, and cos(π/2) = 0,

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\bf tan\left(x+\frac{\pi }{2}  \right)=-cot(x)\\\\&#10;-------------------------------\\\\&#10;tan\left(x+\frac{\pi }{2}  \right)\implies \cfrac{sin\left(x+\frac{\pi }{2}  \right)}{cos\left(x+\frac{\pi }{2}  \right)}&#10;\\\\\\&#10;\cfrac{sin(x)cos\left(\frac{\pi }{2}  \right)+cos(x)sin\left(\frac{\pi }{2}  \right)}{cos(x)cos\left(\frac{\pi }{2}  \right)-sin(x)sin\left(\frac{\pi }{2}  \right)}\implies \cfrac{sin(x)\cdot 0~~+~~cos(x)\cdot 1}{cos(x)\cdot 0~~-~~sin(x)\cdot 1}&#10;\\\\\\&#10;\cfrac{cos(x)}{-sin(x)}\implies -cot(x)
7 0
3 years ago
Give my answer in terms of pi and state it's units
Soloha48 [4]

Answer:

113.1 square mm

Step-by-step explanation:

A=πr2=π·62≈113.09734

3 0
3 years ago
Read 2 more answers
14.) Write an equation of a line with the given slope and y-intercept.
melomori [17]

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Step-by-step explanation:

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4 0
3 years ago
Last year 40 people adopted a manatee through Fia's Foundation.This year 30% more people adopted a manatee. How many more people
Nana76 [90]
Convert 30% into a decimal. Divide the percentage by 100:

30 / 100 = 0.3

The problem can be solved with the following equation:

0.3(40) = difference

Multiply 0.3 by 40.

0.3 * 40 = 12

12 more people adopted a manatee this year.
7 0
3 years ago
A broker has calculated the expected values of two different financial instruments X and Y. Suppose that E(x)= $100, E(y)=$90 SD
Sveta_85 [38]

Expectation is linear, meaning

E(<em>a X</em> + <em>b Y</em>) = E(<em>a X</em>) + E(<em>b Y</em>)

= <em>a </em>E(<em>X</em>) + <em>b</em> E(<em>Y</em>)

If <em>X</em> = 1 and <em>Y</em> = 0, we see that the expectation of a constant, E(<em>a</em>), is equal to the constant, <em>a</em>.

Use this property to compute the expectations:

E(<em>X</em> + 10) = E(<em>X</em>) + E(10) = $110

E(5<em>Y</em>) = 5 E(<em>Y</em>) = $450

E(<em>X</em> + <em>Y</em>) = E(<em>X</em>) + E(<em>Y</em>) = $190

Variance has a similar property:

V(<em>a X</em> + <em>b Y</em>) = V(<em>a X</em>) + V(<em>b Y</em>) + Cov(<em>X</em>, <em>Y</em>)

= <em>a</em>^2<em> </em>V(<em>X</em>) + <em>b</em>^2 V(<em>Y</em>) + Cov(<em>X</em>, <em>Y</em>)

where "Cov" denotes covariance, defined by

E[(<em>X</em> - E(<em>X</em>))(<em>Y</em> - E(<em>Y</em>))] = E(<em>X Y</em>) - E(<em>X</em>) E(<em>Y</em>)

Without knowing the expectation of <em>X Y</em>, we can't determine the covariance and thus variance of the expression <em>a X</em> + <em>b Y</em>.

However, if <em>X</em> and <em>Y</em> are independent, then E(<em>X Y</em>) = E(<em>X</em>) E(<em>Y</em>), which makes the covariance vanish, so that

V(<em>a X</em> + <em>b Y</em>) = <em>a</em>^2<em> </em>V(<em>X</em>) + <em>b</em>^2 V(<em>Y</em>)

and this is the assumption we have to make to find the standard deviations (which is the square root of the variance).

Also, variance is defined as

V(<em>X</em>) = E[(<em>X</em> - E(<em>X</em>))^2] = E(<em>X</em>^2) - E(<em>X</em>)^2

and it follows from this that, if <em>X</em> is a constant, say <em>a</em>, then

V(<em>a</em>) = E(<em>a</em>^2) - E(<em>a</em>)^2 = <em>a</em>^2 - <em>a</em>^2 = 0

Use this property, and the assumption of independence, to compute the variances, and hence the standard deviations:

V(<em>X</em> + 10) = V(<em>X</em>)  ==>  SD(<em>X</em> + 10) = SD(<em>X</em>) = $90

V(5<em>Y</em>) = 5^2 V(<em>Y</em>) = 25 V(<em>Y</em>)  ==>  SD(5<em>Y</em>) = 5 SD(<em>Y</em>) = $40

V(<em>X</em> + <em>Y</em>) = V(<em>X</em>) + V(<em>Y</em>)  ==>  SD(<em>X</em> + <em>Y</em>) = √[SD(<em>X</em>)^2 + SD(<em>Y</em>)^2] = √8164 ≈ $90.35

8 0
4 years ago
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