Question

Courtney is ordering nachos at a restaurant, and the server tells her that she can have up to three toppings: pico de gallo, onions, and steak. Since she cannot decide how many of the toppings she wants, she tells the server to surprise her. If the server randomly chooses which toppings to add, what is the probability that Courtney gets just onions and steak

Answer 1

Answer:

$Probability = \frac{1}{9}$

Step-by-step explanation:

Given

Toppings: Pico de gallo, Onions and Steak

Required

The probability of getting Onions and Steak

The probability is calculated using:

$Probability = P(Onion)\ and\ P(Steak)$ --- because the events are independent

$P(Onion) = \frac{n(Onion)}{Total}$

$P(Onion) = \frac{1}{3}$

$P(Steak) = \frac{n(Steak)}{Total}$

$P(Steak) = \frac{1}{3}$

So, we have:

$Probability = P(Onion)\ and\ P(Steak)$

$Probability = P(Onion)\ *\ P(Steak)$

$Probability = \frac{1}{3} * \frac{1}{3}$

$Probability = \frac{1}{9}$