Answer:
There are 801 box seats and 9612 regular seats.
explanation:
Let the number of box seats be x,
Then the regular seats is 12x
The sum of seats equals to 10,413
<u>Solve:</u>
12x + x ➙ 10,413
13x ➙ 10413
x ➙ 801
There are 801 box seats.
<u>Find for regular seats:</u>
➙ 12(x)
➙ 12(801)
➙ 9612
There are 9612 regular seats.
<span>P - 3 1/6 = -2 1/2
3 1/6- 21/2
p=2/3 </span>
Answer:
-3x^2+6x-157
Step-by-step explanation:
C + a = 140......a = 140 - c
5.3c + 9.4a = 1086.4
5.3c + 9.4(140 - c) = 1086.4
5.3c + 1316 - 9.4c = 1086.4
5.3c - 9.4c = 1086.4 - 1316
-4.1c = - 229.6
c = -229.6 / -4.1
c = 56......so their were 56 child tickets sold