All categories

2 years ago

Explain how place value could be used to find the difference of 4.23 and 2.75

1 answer:

6 0

You can use place value to align the numbers together so you can subtract correctly. Match the ones, tenths, and hundredths digits together to subtract.

4.23
2.75

then you can subtract correctly without any mistakes in place value

You might be interested in

Define the opposite and the absolute value of 6

Archy [21]

Hello :
the opposite is : -6
the absolute value is : 6

8 0

3 years ago

HELP ASAP GIVING BRANLIST 100 POINTS!!!

Sedbober [7]

Rate of change between 1 and 3: find the y values for 1 and 3:

Rate of change = (6-1) / (3-1) = 5/2

Rate of change from 2 and 4:

= (10-3) / (4-2) = 7/2

The rate from 2 to 4 is larger because 7/2 is larger than 5/2

6 0

2 years ago

Read 2 more answers

List the integers within the interval <img src="https://tex.z-dn.net/?f=%20%208%20%5Cleqslant%20x%20%3C%2016" id="TexFormula

Vera_Pavlovna [14]

Answer:

list the integers within the interval

Step-by-step explanation:

Greater than or equal to 8, so 8 is part of this list.

Less than 16, so 16 is not in this list.

6 0

2 years ago

Read 2 more answers

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Can somebody tell me how too simplify this expression 3(5*+2)

Pie

Answer:

15+6

Step-by-step explanation:

You would need to multiply 3*5 then 3*2 and then put 15+6

6 0

2 years ago

Read 2 more answers