A = 28
b = 7
a = 28 * (5/28) = 5
b = 7 * (5/28) = 5/4
Hello! I would love to help!
Let's think...
What number times 2 plus that number is equal to 71.
Let's set up an equation!
What number times 2 (2x) + that number (x) is equal to 71?
Let's write the formal equation now!
2x + x = 71
Let's solve!
Start by combining like terms!
2x +x is 3x
Okay, now we have 3x=71
Let's solve by dividing each side by 3.
Now we have 23.667 or 23 2/3=x
So, the first number is 23 2/3
Let's multiply that by 2 to get the other number!
23 2/3*2= 47 1/3
So, the two answers are 47 1/3 and 23 2/3.
To check, you can add them together, and see if it comes out as 71.
47 1/3 + 23 2/3 = 71
Those are the right answers!
Hope this helps! Comment if you have questions! :)
The answer is 7x + 5y hope this helps!
Answer:
x ≈ 7.2
Step-by-step explanation:
Based o. The secant-tangent theorem, we would have the following:
x² = (9 + 4) * 4
x² = 13 * 4
x² = 52
x = √52
x ≈ 7.2
Answer:
By pigeon hole principle, at least 2 subsets of A have same sum
Step-by-step explanation:
Let A = {x1, x2, . . . , x12} where i ≤ xi≤150
for any 6 element subset S of A, the sum of numbers in S is at least 6 since all integers are positive and it is at most 150+149+148+147+146+145= 885. so we consider number of pigeon holes = number of possible sums= 885 and number of pigeons = number of subsets of A of size 6= ¹²C₆= 924
Since number of pigeons is greater than number of pigeon holes, by pigeon hole principle, at least 2 subsets of A have same sum