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Kay [80]
3 years ago
8

7.(03.02) What is the factored form of 3x2 + 5x – 12? (1 point) (3x + 3)(x + 4) (3x - 1)(x – 4) (3x + 4)(x - 3) (3x – 4)(x + 3)​

Mathematics
2 answers:
mash [69]3 years ago
6 0

Answer:

Hope it can help you... .

If u understand my answer, you can mark me as a brainlist.....

g100num [7]3 years ago
4 0

Answer:

(x + 3)(3x - 4)

Step-by-step explanation:

Given

3x² + 5x - 12

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 12 = - 36 and sum = + 5

The factors are + 9 and - 4

Use these factors to split the x- term

3x² + 9x - 4x - 12 ( factor the first/second and third/fourth terms )

= 3x(x + 3) - 4(x + 3) ← factor out (x + 3) from each term

= (x + 3)(3x - 4)

Thus

3x² + 5x - 12 = (3x - 4)(x + 3) ← in factored form

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21 divided by x = -7 Can you PLS SOLVE X
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Each year, more than 2 million people in the United States become infected with bacteria that are resistant to antibiotics. In p
Olegator [25]

Answer:

Reject <em>H</em>₀. There is a significant difference in drug resistance between the two states.

Step-by-step explanation:

In this case we need to determine whether the data suggest a statistically significant difference between the proportions of drug-resistant cases in the two states.

The significance level of the test is, <em>α</em> = 0.02.

(1)

The hypothesis can be defined as follows:  

<em>H</em>₀: There is no difference between the proportions of drug-resistant cases in the two states, i.e. p_{1} - p_{2}=  0.  

<em>Hₐ</em>: There is a statistically significant difference between the proportions of drug-resistant cases in the two states, i.e. p_{1} - p_{2}\neq  0.  

(2)

Compute the sample proportions and total proportion as follows:

\hat p_{1}=\frac{12}{189}=0.063\\\\\hat p_{2}=\frac{8}{429}=0.019\\\\\hat p=\frac{12+8}{189+429}=0.032\\

Compute the test statistic value as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat p(1-\hat p)\times [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.063-0.019}{\sqrt{0.032(1-0.032)\times [\frac{1}{189}+\frac{1}{429}]}}\\\\=2.86

The test statistic value is 2.86.

(3)

The decision rule is:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

Compute the p-value as follows:

p-value=2\cdot P(Z>2.86)=2\times 0.00212=0.00424

<em>p</em>-value = 0.00424 < <em>α</em> = 0.02.

The null hypothesis will be rejected at 0.02 significance level.

Reject <em>H</em>₀. There is a significant difference in drug resistance between the two states.

7 0
3 years ago
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