Using the identity sin^2(t)+cos^2(t)=1
and
given sin(t)=0.3,
we can find cos(t) by substituting
sin^2(t)+cos^2(t)=1
0.3^2+cos^2(t) = 1
cos^2(t)=1-0.3^2=1-0.09=0.91
cos(t)=sqrt(0.91)= 0.954 ≠ 0.6
So the given proposition is false.
What do you need answered?
9514 1404 393
Answer:
B. x = -6, x = 4
Step-by-step explanation:
The constant on the left wants to be 1, the square of half the x-coefficient. We can get it to be that value by adding 8 to the equation.
x² +2x +1 = 25
(x +1)² = 25 . . . . . . . rewrite the left side as a square
x +1 = ±√25 = ±5 . . . . take the square root
x = -1 ±5 . . . . . . . . . subtract 1
x = -6 or x = 4
Answer:
0-2 x-intercepts and 0-1 y-intercepts
Step-by-step explanation:
A quadratic function can have anywhere from 0 to 2 x-intercepts. This is possible because a function can have 0, 1, or 2 solutions.
A parabola can also have either 0 or 1 y intercepts. It is possible for the function to not intercept the y axis at all, and it is also possible for it to intercept it exactly one time.
The answer is 12. you first divide 20 by 4 and get 5. then you subtract 5 by 5 and get 0. then you add 12 plus 0 and get 12
Hope I Helped :D
