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Liula [17]
2 years ago
6

3x-5y=-6 -9x-5y=18 whats the answer

Mathematics
2 answers:
Firlakuza [10]2 years ago
4 0
\left \{ {{3x-5y=-6\ \ | *3} \atop {-9x-5y=18}} \right. \\\\  \left \{ {{9x-15y=-18} \atop {-9x-5y=18}} \right. \\+----\\add\ both\ equations\\\\
-20y=0\ \ \ | divide\ by \ -20\\\\
y=0\\\\
3x-5y=-6\ \ \ \ add\ 5y\\\\
3x=-6+5y\ \ \ | divide\ by\ 3\\\\
x=\frac{-6+5y}{3}=\frac{-6+0}{3}=-2\\\\ x=-2\\ y=0
rodikova [14]2 years ago
3 0
We can eliminate the  y term by multiplying by -1 and adding
-9x-5y=18
multiply -1
9x+5y=-18
add
     3x-5y=-6
  +<u> 9x+5y=-18</u>
     12x+0y=-24
12x=-24
divide by 12
x=-2

subsitute
3(-2)-5y=-6
-6-5y=-6
add 6 to both sides
-5y=0
y=0

x=-2
y=0
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larisa86 [58]

Answer:

k = -12

Step-by-step explanation:

<u>Step 1:  Divide both sides by -8</u>

<u />96 / -8 = -8k / -8

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Answer: k = -12

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bearhunter [10]
<h3>Answer:</h3>

x=2

<h3>Solution:</h3>
  • In order to isolate x, we should first of all take the square root of both sides.
  • If we take the square root of the left-hand side, we will get
  • x-\displaystyle\frac{1}{2}
  • How about the right-hand side? Well, we should take the square root of the numerator (9) and the denominator (4)
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  • x-\displaystyle\frac{1}{2} =\frac{3}{2}}
  • Move -1/2 to the right:
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Hope it helps.

Do comment if you have any query.

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3 years ago
What is the solution of the system?
Kryger [21]
Greetings!

Solve the System, using Elimination:
\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.

Multiply Equation #2 by 2:
\left \{ {{4x+2y=18} \atop {2(2x+3y)=2(15)}} \right.

\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.

Eliminate variable x:
-\frac{ \left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.}{0x-4y=-12}

4y=-12

Divide both sides by 4:
\frac{4y}{4}= \frac{12}{4}

y=3

Input this value into one of the Equations: 
4x+2y=18

4x+2(3)=18

Simplify:
4x+6=18

(4x+6)+(-6)=(18)+(-6)

4x=12

Divide both sides by 4.
\frac{4x}{4}= \frac{12}{4}

x=3

The Solution to this System (The Point of Intersection):
\boxed{(3,3)}

I hope this helped!
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