The area of a triangle is related to the base and height of the triangle by the formula a = bh/2. Rewrite this equation with b s
2 answers:
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Answer:
<em>The area of the trapezium is 168</em>
Step-by-step explanation:
<u>Area of a Trapezoid</u>
Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:
The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:
The side BC can be found as half the difference of the bases:
Solving for EC:
Now we have the height, calculate the area:
A = 168
The area of the trapezium is 168
<h3>hello!</h3>
In order to solve this equation, we need to take the square root of both sides (in order to get rid of the square and isolate x, because we are asked to determine the value(s) of x)
x²=36
√x²=√36
x=6
Is this the only solution?
<em>A negative times a negative is a </em><em>positive...</em>
-6 is another solution of this equation! :)
Hence, the answers are:-
Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)