Population of the city of Atlantis on March 30, 2003 = 193,000 No. of new active cases of TB occurring between January 1 and Jun

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Population of the city of Atlantis on March 30, 2003 = 193,000 No. of new active cases of TB occurring between January 1 and Jun

e 30, 2003 = 92 No. of active TB cases according to the city register on June 30, 2003 = 338 The incidence rate of active cases of TB for the 6-month period was______.

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1 answer:

zubka84 [21] · Answer 1 · 2022-01-10T02:44:16+03:00

Answer:

4.77 × 10^-4

Explanation:

Given that

Population of the city of Atlantis on March 30, 2003 = 193,000

No. of new active cases of TB occurring between January 1 and June 30, 2003 = 92

No. of active TB cases according to the city register on June 30, 2003 = 338

So, the incident rate of active cases is shown below:

= (No. of new active cases of TB occurring between January 1 and June 30, 2003) ÷ (Population of the city of Atlantis on March 30, 2003 - No. of active TB cases according to the city register on June 30, 2003)

= (92) ÷ (193,000 - 338)

= (92) ÷ (192,662)

= 4.77 × 10^-4