Question

Population of the city of Atlantis on March 30, 2003 = 193,000 No. of new active cases of TB occurring between January 1 and June 30, 2003 = 92 No. of active TB cases according to the city register on June 30, 2003 = 338 The incidence rate of active cases of TB for the 6-month period was______.

Answer 1

Answer:

4.77 × 10^-4

Explanation:

Given that

Population of the city of Atlantis on March 30, 2003 = 193,000

No. of new active cases of TB occurring between January 1 and June 30, 2003 = 92

No. of active TB cases according to the city register on June 30, 2003 = 338

So, the incident rate of active cases is shown below:

= (No. of new active cases of TB occurring between January 1 and June 30, 2003) ÷ (Population of the city of Atlantis on March 30, 2003  - No. of active TB cases according to the city register on June 30, 2003)

= (92) ÷ (193,000 - 338)

= (92) ÷ (192,662)

= 4.77 × 10^-4