0 = 4x²<span> + 2x – 1
this equation is already ordered by degree, so it's in the correct form. the standard form of a parabola is like so: 0 = A</span>x² + Bx - C
that's exactly how you plug values into the quadratic formula. the coefficient for your squared value, A, is 4. take the coefficients from your other numbers as well.
a = 4
b = 2
c = -1
Answer:
Step-by-step explanation:
From the given figure it is clear that the stop board is a regular hexagon and ∠I is an exterior angle of the regular hexagon.
Exterior angle of a regular polygon with n sides 
In a regular hexagon number of sides: n =6
Exterior angle of a regular hexagon 
Since ∠I is an exterior angle of the regular hexagon, therefore, 
.
If this is for E2020 the answer is
D)<span>No, his value of </span><span> should be positive because an even exponent indicates a positive value.
thats why it was wrong</span>
Answer:
2 sqrt(3) -2i
Step-by-step explanation:
If we have the magnitude and the theta
z = |z| cos theta + i |z| sin theta
= 4 cos 330 + i 4 sin 330
=4 (sqrt(3)/2) + 4i (-1/2)
= 2 sqrt(3) -2i
Answer:
<h2>hey I'm I'm not sure but I think that the answer is 3</h2>
