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Taya2010 [7]
3 years ago
9

Pls helpeddddddddddddddd

Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Remark

The easiest way to do this is to Substitute for y in the top equation.

2x + 4y = 18                         Divide by 2

2x/2 + 4y/2 = 18/2

x + 2y = 9

Substitute -3x + 2 in for y in the equation above

x + 2(-3x + 2) = 9

x - 6x + 4 = 9                    

Combine like terms on the left

-5x + 4 = 9                      

Subtract 4 from both sides.

-5x + 4-4 = 9- 4

-5x = 5

Divide by -5

-5x/-5 = 5/-5

x = - 1

That makes A and C incorrect.

y = -3x + 2

y = -3(-1) + 2

y = 3 + 2

y = 5

The correct answer should be (-1,5) which is B

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HELPPPP PLEASE HELP ME WITH BASIC MATH I REALLY APPRECIATE IT ((WILL MARK AS BRAINLIEST))​
Yakvenalex [24]

Answer:

3) 522

4) 468

Step-by-step explanation:

hello!

3) in the question, it says the cross section is a square, and the area of PQRS is 81.

for the square, we know that the length and height have to be the same, so if the area is 81, then we know the sides are both 9 because 9*9 is 81 and they're the same numbers multiplied. (same height and length)

with the information that all 4 sides of the square is 9 and the other side is labeled 10, we can figure out the rest.

both squares : 81+81=162

both 10 by 9 sides: 90+90=180

both 10 by 9 sides (top and bottom): 90+90=180

total surface area=162+180+180=522

4) for this problem, we can see that the triangle is a right triangle.

to solve the area of the triangle, we can do (9*12)/2=108/2=54.

there are two sides with triangles, so we double 54 (54*2=108)

9 by 10 side: 90

10 by 12 side: 120

now for the last slide, theres no information on the length. the formula for the diagonal is

a^2+b^2=c^2

which is

9^2+12^2=81+144=255=15^2

with this, the area of the rectangular side gives us 10*15 which is 150.

adding it together, we get

108+90+120+150=468.

hope this helps!

7 0
3 years ago
32) (a)-(c) pre calculus
Harrizon [31]
Well, remember we can't take the square root of a negative

so we see that we have \sqrt{1-x^2}
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain


b. for a TI-84, go to y-editor then input 4x \sqrt{1-x^2} for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7



A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7


8 0
3 years ago
I needddd helppp please
Montano1993 [528]

Answer:

X=66°

Step-by-step explanation:

Because it is an isosceles triangle, the 2 missing angles are going to be the same size.

Subtract  48 from the total degree of the triangle which is 180.

180-48= 132

now you di ed that by 2 and you’ll know the missing angle.

132/2= 66

5 0
3 years ago
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algol13
I believe the answer is A
4 0
3 years ago
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Nikolay [14]

Answer:

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3 0
3 years ago
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