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Ede4ka [16]
3 years ago
5

Factor 2x2 + 11x + 15 using algebra tiles and symbolically

Mathematics
1 answer:
fomenos3 years ago
7 0
2x^{2}+11x+15=2x^{2}+6x+5x+15=2x(x+3)+5(x+3)= \\  \\ (2x+5)(x+3)
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3a2 + 2a + 2a2 is equal to​
yanalaym [24]

Answer:

  5a^2 +2a

Step-by-step explanation:

Like terms are ones with the same exponent of x. They can be combined.

  3a^2 +2a +2a^2

  = (3a^2 +2a^2) +2a

  = (3+2)a^2 +2a

  = 5a^2 +2a

4 0
2 years ago
Read 2 more answers
All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
2 years ago
Question:
snow_tiger [21]

Answer:

A (first picture)

Step-by-step explanation:

Based on the picture, the lines are both perpendicular and the red line splits AB into two equal parts (bisects it), so it must represent the perpendicular bisector of AB.

5 0
2 years ago
Solve <br> x-3/x+4 - 3x+2/2x+8
vfiekz [6]
\left[x _{2}\right] = \left[ 6+\sqrt{33}\right][x​2​​]=[6+√​33​​​]
8 0
3 years ago
Need help please !!!
irina1246 [14]

sin^2 x + 4 sinx +3       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


factor the numerator


(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

cos^2 x                        1 - sinx


cos^2 = 1-sin^2x

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

1- sin^2x                       1 - sinx

factor the denominator

(sinx +3) (sinx+1)       3 + sinx

--------------------------  =  -------------------

(1-sinx ) (1+sinx)                   1 - sinx

cancel the common term (1+sinx)  and (sinx +1)

(sinx +3)                       3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx


reorder the first term

3+sinx                           3 + sinx

--------------------------  =  -------------------

(1-sinx )                           1 - sinx

3 0
3 years ago
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