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Anni [7]
3 years ago
6

Show that the series is convergent by the alternating series test, and find the number of terms necessary to estimate the sum of

the series with an error of less than 0.05.

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

6 terms

Step-by-step explanation:

2 − 2/4 + 2/9 − 2/16 + ...

∑ (-1)ⁿ⁺¹ 2 / n²

Applying alternating series test:

lim(n→∞) 2/n² = 0

2/(n+1)² < 2/n², so the series is decreasing.

Therefore, the series converges.

2/(n+1)² < 0.05

(n+1)²/2 > 20

(n+1)² > 40

n+1 > 6.32

n > 5.32

n = 6

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Confidence intervals:

The larger the sample size, the closest the parameter estimate is to the value of the population, as the margin of error of confidence intervals is inversely proportional to the sample size, that is, a greater sample leads to a smaller margin of error.

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2 years ago
Will brought 5 boxes of candy at the theater if each box of candy cost $ 2.30 and he paid with a twenty dollar bill how much cha
daser333 [38]

Answer:

8.50$

Step-by-step explanation:

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3 0
2 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
Basile [38]
1.Disc method.
In this method the volume is given by:

\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}

so:

V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}

A) Function f(x)=x^2 over the interval [1,3]
B) We use disk method and f(x) is function of variable x, so we <span>rotate the curve about the x-<span>axis.


2. Shell method.

In this case volume is given by:

</span></span>\boxed{V=2\pi\int\limits_a^bx\cdot f(x)\,dx}

So there will be:

V=\pi\int\limits_1^3x^4\,dx=\dfrac{2}{2}\cdot\pi\int\limits_1^3x^4\,dx=2\pi\int\limits_1^3\dfrac{x^4}{2}\,dx=&#10;\boxed{2\pi\int\limits_1^3x\cdot\dfrac{x^3}{2}\,dx}

A) Function f(x)=\dfrac{x^3}{2} over the interval [1,3]
B) We use shell method and f(x) is function of variable x, so we <span>rotate the curve about the y-<span>axis.</span></span>
3 0
2 years ago
Guys omg please someone answer this asap this is due tmmr
MrRissso [65]

Answer:

First, break the shape into smaller shapes.

Bigger rectangle: 5m, 8m

Thin rectangle: 7m, 3m

Thinner rectangle: 8m, 2m

We will call the bigger rectangle <u>B</u>, the thin rectangle <u>R</u>, and the thinner rectangle <u>r</u>.

Step-by-step explanation:

B = 8 • 5 = 40

R = 7 • 3 = 21

r = 2 • 8 = 16

Add the areas together:

40 + 21 + 16 = 77

Therefore, the area is <u>77 meters.</u>

4 0
1 year ago
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