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2 years ago

A European swallow flies about 14 meters in 1 second.

Mathematics

2 answers:

ivann1987 [24]2 years ago

5 0

Answer:

It could fly 12.6 kilometers.

Step-by-step explanation:

The European swallow fly speed is 12 meters per second.

We have to calculate how many kilometers it could fly in 15 minutes.

This can be calculated using the equivalent factors for each of the units:

- 1 km is equivalent to 1,000 meters.

- 1 minute is equivalent to 60 seconds.

11111nata11111 [884]2 years ago

5 0

ANSWER:
12.6 km

EXPLANATION:
If the swallow fly goes 14 m/s then you can multiply 14x60 to get 840m per minute.
From there you multiply 840x15 and get 12,600m for 15 minutes. You then divide 12,600/1000 to convert meters into kilometers and you get 12.6km.

Hope this helped!

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3 years ago

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Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin

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Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let $\mu$ = mean duration of 15-sided union rugby games after the meeting.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 185 minutes {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, $H_A$ : $\mu$ < 185 minutes {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean duration of 15-sided union rugby games = 179 min

s = sample standard deviation = 12 minutes

n = sample of 15-sided rugby games = 36

So, the test statistics = $\frac{179-185}{\frac{12}{\sqrt{36} } }$ ~ $t_3_5$

= -3

The value of t test statistics is -3.

Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

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4 years ago

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Step-by-step explanation:

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4 years ago

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The completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)

<h3>How to find the factors of a quadratic expression?</h3>

If the given quadratic expression is of the form ax^2 + bx + c, then its factored form is obtained by two numbers alpha( α ) and beta( β) such that:

$b = \alpha + \beta \\ ac =\alpha \times \beta$

Then writing b in terms of alpha and beta would help us getting common factors out.

Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any trial and error.

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So we've to find two numbers such that:

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Their product = $ac = 4\times 49 = 196$

We can see that 196 is square of 14, and that 14 added twice forms 28, thus:

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Writing b = 28 as sum of 14 twice, we get:

$4x^2 + 28x + 49 = 4x^2 + 14x + 14x +49 \\4x^2 + 28x + 49 = 2x(2x+7) + 7(2x + 7)\\4x^2 + 28x + 49 = (2x+7)(2x+7)$

Thus, the completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)

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