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3 years ago

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[FIRST TO ANSWER GETS BRAINLIEST] Here is a rectangle ABCD. The length of the rectangle is increased by 10%. The width of the re

ctangle is increased by 5%. Find the percentage increased in the perimeter of tge rectangle.

1 answer:

erastovalidia [21]3 years ago

6 0

New length = 30x110% = 33cm
new width = 20x105% = 21cm

original perimeter = 30x2 + 20x2
= 60 + 40 = 100
new perimeter = 33x2 + 21x2
= 66 + 42 = 108

increase in perimeter = 108-100 = 8
percentage increase = 8/100 x 100% = 8%

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Please please answer this correctly

Katarina [22]

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3 years ago

Read 2 more answers

Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago

A car dealership pays a wholesome price of $12,000 to purchase a vehicle. The car dealership wants to make a 32% profit. The car

cestrela7 [59]

Answer:

$102.96

Step-by-step explanation:

Lets take this one part at a time.

the dealership pays 12000 for the car, so they start at -12000 for how much money they have.

The dealership wants to make a 32% profit. This means they want to make back the 12000 plus 32% of that. what is 32% of 12000? just multiply 12000 bty .32 In the end it works out that the price they sell it for is 15840

I do want to mention that there is a chance the 32% might also be accounting the bonus. So in other words the dealership spent 12000 for the car then however much in paying the bonus, and they want to make a 32% profit on both of these combined. I do not think that is what it is asking for, but I wanted to mention it.

Anyway, with a sales price of $15,840 it says the bonus is 6.5% of that. to find that just do the multiplication .065 * 15840 = 1029.60. So this is the bonus normally.

Now the question says the salesperson offers a 10 percent discount. This changes the sales price (by 10%) and the bonus they earn. let's calculate both.

First 10% discount of the sales price is .9*15840 = 14,256

Then 6.5% of that is .065*14256 = 926.64 So this is the new bonus.

The question wants the difference of the two bonuses, and difference is subtraction. so 1029.60 - 926.64 = 102.96 So if the salesperson offers a 10% discount they lose $102.96

5 0

3 years ago

Which choice is the equation of a line that passes through (9, -3) and is parallel to the line represented by this equation? y=5

miskamm [114]

Answer:

$y+3=\frac{5}{3}(x-9)$ or $y=\frac{5}{3}x-18$

Step-by-step explanation:

step 1

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are the same

we have

$y=\frac{5}{3}x-4$

therefore

The slope m of the line parallel to the given line is

$m=\frac{5}{3}$

step 2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{5}{3}$

$point\ (9,-3)$

substitute

$y+3=\frac{5}{3}(x-9)$ ----> equation of the line in point slope form

step 3

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$y+3=\frac{5}{3}(x-9)$

Isolate the variable y

$y+3=\frac{5}{3}x-15$

$y=\frac{5}{3}x-15-3$

$y=\frac{5}{3}x-18$

7 0

3 years ago

Suppose a contest allows you to spin a wheel for a prize..

Dvinal [7]

Answer:

Step-by-step explanation:

I pretty sure its A

hope it helps

-Delilah

8 0

3 years ago