i think it would be b cause the plant will always grow
Answer:
The percentage of the population that is heterozygous for this trait is 48%
Explanation:
They are two alleles, the phenylthiocarbamide tasters (PTC) and the non phenylthiocarbamide tasters (non PTC). PTC testers are dominant and non PTC tasters are recessive.
let the frequency of the dominant allele(A) be p
and the frequency of the recessive allele(a) be q
We are told that 64 percent of people living in a remote, isolated mountain village can taste phenylthiocarbamide (PTC) and must, therefore, have at least one copy of the dominant PTC taster allele (that is AA and Aa)
Frequency of AA = p², Frequency of Aa = 2pq and Frequency of aa = q²
Therefore p² + 2pq = 64% = 0.64
According to Hardy–Weinberg:
p² + 2pq + q² = 1 and
p + q = 1
Since p² + 2pq = 0.64
∴ 0.64 + q² = 1
q² = 1 - 0.64 = 0.36
q = √0.36 = 0.6
Since p + q = 1
p = 1 - q = 1 - 0.6 = 0.4
The frequency of heterozygous = 2pq = 2 × 0.4 × 0.6 = 0.48
Therefore the percentage of the population that is heterozygous for this trait is 48%
Random distribution is the probable distribution pattern of opossums.
Explanation:
The opossums are the member of low density population. They are sparsely distributed because of the low number. There are troubles for them to find a mate.
Their habitat makes them solitary as they have flexible dietary habits. they are terrestrial animals living in burrows and are nocturnal.
They have random distribution pattern. The opossums are distributed in the population as random. The mates in opossums do not have choices of mates and the environment conditions in which they live are stagnant.(having no social life). Random interaction is seen in <em>species which do not have any social bonding</em> between the species of the animals or plants.
Answer:
After watching a plant for a week, you determine it needs more sunlight
Explanation
Inference is a conclusion so you concluded the plant needs more sunlight.
