Umm just do the problem with 7 in the place of N
Easiest method you can apply (Cramer's one). <em>"</em><em>Thanks</em><em> </em><em>me</em><em>"</em><em> </em>if i've been helpful
729, <span>â6561 is the answer</span>
Answer:
3.5
Step-by-step explanation:
First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3