Point slope is y-y1= m(x-x1) where m is slope
Plug the values in:
y-(-8)=3(x-8)
Simplify:
y+8=3(x-8)
Answer:
Step-by-step explanation:
Group like terms 6y-2y= 2-1-2
When a number goes over the equal sign= positive + changes to negative, vice versa.
So final answer is 4y= -1= -4y
Because 4 is decided by -1
Answer:-126f-108
Step-by-step explanation:
9(-9f - 2)-9(5f +10)
-81f - 18 -9(5f + 10)
- 81f - 18 - 45f -90
- 126f - 18 - 90
-126f -108
which give you the answer -126f - 108
A) it is left skewed
B) the median is 5
C) the mean is 5.15
D) the mean would be more affected (a change of 1.05 versus a change of 0.5).
The majority of the data is to the right of the graph; this means it is left skewed.
To find the median, write all of the data values out:
2, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7
The middle value is 5.
We find the sum of this set of values and divide by 13, the number of data points, to find the mean:
2+3+4+4+5+5+5+6+6+6+7+7+7 = 67/13 = 5.15
If we added an additional data value at 20, the new median would be 5.5. The new mean would be (67+20)/14 = 6.2. The mean changes more than the median.
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.