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3 years ago

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There are 54 players in a beach volleyball club. Nine of the players cannot attend a game night. The coach needs to make even te

ams with the players that are there. What fraction of the players, in sixths, are at the game night?

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

Answer:

5/6

Step-by-step explanation:

One-sixth of the club is 54/6 = 9 players. That's the number not there. Since 1/6 is missing, 5/6 of the players are at game night.

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. Here is an equation 2x + 9 = -15. Write three different equations that have the same solution as 2x + 9 = -15. Show or explain

Anettt [7]

Answer:

1. $x-3=-15$
2. $2x=-24$
3. $2x-3=-27$

Step-by-step explanation:

Given the following question:

$2x+9=-15$

To find three equations that have the same solution as the given equation we have to first solve the equation.

$2x+9=-15$
$9-9=0$
$-15-9=-24$
$2x=-24$
$2x\div2=x$
$-24\div2=-12$
$x=-12$

<u>Equation one:</u>
$x-3=-15$
$-3+3=0$
$-15+3=-12$
$x=-12$

<u>Equation two:
</u> $2x=-24$
$2x\div2=x$
$-24\div2=-12$
$x=-12$

<u>Equation three:</u>
$2x-3=-27$
$-3+3=0$
$-27+3=-24$
$-24\div2=-12$
$x=-12$

Hope this helps.

4 0

2 years ago

Graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 2, negative 1, and 2

xz_007 [3.2K]

Hello,

A cubic polynomial with -2,1,2 as roots is
f(x)=k*(x+2)(x+1)*(x-2)=k(x²-4)(x+1)=k(x^3+x²-4x-4)

Looking the answers ==>k=1

==>Answer A

6 0

3 years ago

Read 2 more answers

Melissa has reached her credit card limit of $6,500. Since Melissa has poor credit history, the annual interest rate on her cred

GrogVix [38]

You my 220+235 and then you get the Nader

4 0

3 years ago

A = {red, green, blue, yellow} B = {orange, purple, black, blue} Find A U B.

Kipish [7]

Answer:

A∪B={ red , green , blue , yellow , orange , purple , black }

Step-by-step explanation:

Let A and B be two subsets Then A∪B represents the union of the two subsets which means that it consists of the elements present in A or B or in both A and B.

given A={ red , green , blue , yellow }

B={ orange , purple , black , blue }

Now A∪B={ red , green , blue , yellow , orange , purple , black }

for getting above first write all the elements in A then start writing elements of B and skip those elements of b which are already present in A and write all the elements of B.

8 0

4 years ago

Read 2 more answers

The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.

Lilit [14]

Answer:

We conclude that the true mean life of a biomedical device is greater than 5200 hours.

Step-by-step explanation:

We are given that the life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed. For this a random sample of 15 devices is selected and found to have an average life of 5323.8 hours and a sample standard deviation of 220.9 hours.

We have to test that the true mean life of a biomedical device is greater than 5200 or not.

Let, Null Hypothesis, $H_0$ : $\mu \leq$ 5200 {means that the true mean life of a biomedical device is less than or equal to 5200 hours}

Alternate Hypothesis, $H_1$ : $\mu$ > 5200 {means that the true mean life of a biomedical device is greater than 5200 hours}

The test statistics that will be used here is;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, Xbar = sample average life = 5323.8 hours

s = sample standard deviation = 220.9 hours

n = sample devices = 15

So, test statistics = $\frac{5323.8-5200}{\frac{220.9}{\sqrt{15} } }$ ~ $t_1_4$

= 2.171

Since, we are not given with the significance level, so we assume it to be 5%, now the critical value of t at 14 degree of freedom in t table is given as 1.761. Since our test statistics is more than the critical value of t which means our test statistics will lie in the rejection region. So, we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the true mean life of a biomedical device is greater than 5200 hours.

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3 years ago