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Vladimir [108]
4 years ago
15

Chloe t. followed the procedure of this experiment to determine the empirical formula of a compound of iron (fe) and chlorine (c

l). to do so, she added 2.15 g of zn to a solution containing 1.750 g of fe(x)cl(y). after the reaction was complete, she isolated 0.771 g of fe. the mass of cl in the fe(x)cl(y) solution is
Chemistry
1 answer:
Alexxx [7]4 years ago
8 0

m(\text{Cl}) = 0.979 \; \text{g}

Explanation

The 1.750 \; \text{g} sample contains only the atoms of

  • Iron, \text{Fe}, and
  • Chlorine, \text{Cl}

Thus no matter what natural numbers x and y are, m(\text{Fe}_x\text{Cl}_y) = m(\text{Fe}) + m(\text{Cl}) shall holds.

Recall that zinc \text{Zn} is more reactive than iron as seen in the reactivity series;  Adding zinc to the solution would reduce all iron atoms (regardless of the oxidation state, +2 or +3) to their elementary form, hence displacing them out of the solution. 0.771 \; \text{g} of iron was obtained and therefore m(\text{Fe}) = 0.771 \; \text{g}.

Thus

\begin{array}{lll}m(\text{Cl})& =& m(\text{Fe}_x\text{Cl}_y) - m(\text{Fe})\\ & = &1.750 \; \text{g}- 0.771\; \text{g}\\ &=&0.979\; \text{g}\end{array}


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