Question

A 250.0 mL sample of air at 100.0 K is warmed to 200.0 k at constant pressure .What is the volume of the air sample at the new temperature? Show your work below.

Answer 1

Answer:

500.0 mL

Explanation:

From Charles’ Law, we know that

$\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2 }}$

We can solve this equation to get

$V_{2} = V_{1} \times \frac{ T_{2}}{ T_{1}}$

$V_{2} = \text{250.0 mL} \times \frac{\text{200.0 K}}{\text{100.0 K}} = \textbf{500.0 mL}$