3 Mg + 1 Fe2O3 →2 Fe + 3MgO
Type of Reaction: Single displacement.
Answer:
a. Each set of elements was arranged in special coloumns based on their mass.
Answer:

Explanation:
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In this case, since the modelling of titration problems can be approached via the Henderson-Hasselbach equation to set up a relationship between pH, pKa and the concentration of the acid and its conjugate base, we can write:
![pH=pKa+log(\frac{[NO_2^-]}{[HNO_2]} )](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5BNO_2%5E-%5D%7D%7B%5BHNO_2%5D%7D%20%29)
Whereas the pH is given as 3.14 and the concentrations are the same, that is why the pH would be equal to the pKa as the logarithm gets 0 (log(1)=0); thus, we can calculate the Ka via:

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Answer:
These clouds extend through the lower and mid-layers of the troposphere bringing rain to the surface below.
Explanation:
The bases of clouds in the middle level of the troposphere, given the prefix “alto,”
Answer: Yes
The antibonding orbital is empty. Thus, H2 is a stable molecule.