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Natalka [10]
4 years ago
13

Which conclusion about f(x) and g(x) can be drawn from the table

Mathematics
1 answer:
NeTakaya4 years ago
7 0
<h2>Answer:</h2>

The conclusion that is true about f(x) and g(x) based on the table of values is:

  •      The function f(x) and g(x) are reflections over the y-axis.    
<h2>Step-by-step explanation:</h2>
  • We know that the rule that describes the reflection over the y-axis is:

        (x,y) → (-x,y)

Hence, if we have a function f(x) as:

f(x)=2^x

Then it's reflection over the y-axis is:

f(-x)=2^{-x}\\\\\\f(-x)=(2^{-1})^x\\\\\\f(-x)=(\dfrac{1}{2})^x\\\\i.e.\\\\\\g(x)=(\dfrac{1}{2})^x

Hence, they are reflection over the y-axis.

  • Also, we know that the exponential function of the type:

                y=ab^x

where a>0 is a increasing function if b>1

and is a decreasing function if: 0<b<1

Hence, f(x) is a increasing function and g(x) is a decreasing function.

  • Also, the initial value of a function is the value of function when x=0

when x=0 we see that both f(x)=g(x)=1

i.e. Both f(x) and g(x) have same initial value.

Also,by the graph we may see the relation.

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3 years ago
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A 4-pound bag of sugar contains 454 one-teaspoon servings and costs $3.49. A batch of muffins uses 1 2 cup of sugar. How many wh
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Answer:

a) 19 batches

b) $0.18

Step-by-step explanation:

A 4-pound bag of sugar contains 4 54 one-teaspoon servings and costs $3.49. A batch of muffins uses 1/2 cup of sugar.

1 cup = 48 teaspoons

a) How many whole batches can you make if you use as much of the sugar as possible?

1 batch = 1/2 cups of sugar = 24 teaspoons of sugar

Hence,

24 teaspoons of sugar = 1 batch

454 one-teaspoon servings = x

Cross Multiply

24 × x = 1 × 454

x = 454/24

x = 18.9166666667

Approximately to whole batches = 19 batches

b) What is the cost of sugar for each batch?

454 one-teaspoon servings and costs $3.49 = 19 batches

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19 batches = $3.49

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7 0
3 years ago
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There is multiple names it has, like for example “Zero” and in British English it is “nought” which is often used as an archaic word for nothing, I hope this help’s.

7 0
2 years ago
Find the exact value of cos(theta) for an angle (theta) with tan (theta)= -2/3 and with its terminal side in Quadrant II.
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Answer:

-\frac{3\sqrt{13}}{13}.

Step-by-step explanation:

Since we are in quadrant two, cosine value is negative while sine value is positive.

We are going to use the Pythagorean Identity: 1+\tan^2(\theta)=\sec^2(\theta).

1+(\frac{-2}{3})^2=\sec^2(\theta)

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\frac{9+4}{9}=\sec^2(\theta)

\frac{13}{9}=\sec^2(\theta)

\pm \sqrt{\frac{13}{9}}=\sec(\theta)

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Since cosine and secant are reciprocals then they will have the same sign as along as they both exist.

\sec(\theta)=-\frac{\sqrt{13}}{3}

\cos(\theta)=-\frac{3}{\sqrt{13}}.

I don't see this answer as I'm going to rationalize the denominator.

\cos(\theta)=-\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}.

\cos(\theta)=-\frac{3\sqrt{13}}{13}.

8 0
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Answer:

see below

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3.the equations have the same slope and same y-intercepts. they are the same line so they have infinite solutions

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