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3 years ago

which equation below models the number of years (y) Ariana must leave the money in the account to reach her goal?

Mathematics

2 answers:

baherus [9]3 years ago

6 0

Answer:

Step-by-step explanation:

First of all, the interest is compounded which means that the new principle is the principle from the year before added to the interest from the year before.

So, for example, at the end of the first year she will have accumulated 60 dollars in interest. That 60 dollars is added to the 2000 and the second year will give you 2060 dollars as your principle. That means that anything using 0.03 is incorrect if not with the 1.

A and C are both incorrect.

You don't want to be adding even if you are using 1.03. So that means

D is incorrect.

The answer must be B

Darina [25.2K]3 years ago

3 0

Answer:

The answer is B

Step-by-step explanation:

For these equations, the number inside the parenthesis has to be greater than 1 in order to increase. You also have to multiply what is inside the parenthesis with what is outside.

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1. Evaluate: 4(5) +3(7-2) a. 25 C. 18 d. 40 e. -40

Brrunno [24]

Answer:

Step-by-step explanation:

Simplify the following:

4×5 + 3 (7 - 2)

7 - 2 = 5:

4×5 + 3×5

4×5 = 20:

20 + 3×5

3×5 = 15:

20 + 15

| 2 | 0

+ | 1 | 5

| 3 | 5:

Answer: 35

6 0

3 years ago

I need help with this

olga55 [171]

3:5 -> 6:10, 9:15, 12:20
8:10-> 4:5,16:20, 24:30
6:8 -> 3:4, 12:16, 30:40
6:18 -> 3:9, 12:36, 30:90
4:8 -> 1:2, 8:16, 12:24

3 0

2 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

3 years ago

Emmanuel sections off a part of the backyard of his house to build the rectangular stone patio for his grill. The length of the

liq [111]

Answer: x + 3feet

Step-by-step explanation:

From the question, Emmanuel sections a part of his house backyard in order to build the rectangular stone patio for his grill. We are told that the length of the base is going to be 3 feet more than the width and the width has been defined as x.

Since the length of the base will be 3 feet more than the width and the width is x. Therefore, the length will be:

Length = x + 3feet

5 0

3 years ago

For what value of the constant c does the above equation have x = 2 as the only solution?

Sladkaya [172]

$the \: answer \: is \: - 41$

5 0

3 years ago