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Semenov [28]
2 years ago
14

Please answer these questions ....please....

Mathematics
1 answer:
Katena32 [7]2 years ago
6 0

Answer:

The answer is six

Step-by-step explanation:

and yw :D

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What is the equation of the line that is parallel to the line x = –2 and passes through the point (–5, 4)
Karolina [17]

Answer:

x=-5

Step-by-step explanation:

4 0
3 years ago
8 PTS.
Harman [31]

Answer:

The dependent variable:  the total cost

The independent variable: the amount of books


If the equation is  y = 8x + 200

y would be the dependent variable and x would be the independent variable


I hope this helps.

7 0
2 years ago
What is the width of the rectangle shown below? <br>4x + 3 <br>A = 8x2 – 10x – 12
ozzi

Answer:

<h2><em>2x-4</em></h2>

Step-by-step explanation:

Area of a rectangle = Length * Width

Given parameters

Area A = 8x2 – 10x – 12

Length of the rectangle = 4x+3

Required

Width of the rectangle.

Substituting the given parameters into the formula

8x2 – 10x – 12  = (4x+3)*width

width = 8x2 – 10x – 12 /4x+3

S

Factorizing the numerator

8x² – 10x – 12

= 2(4x²-5x-6)

= 2(4x²-8x+3x-6)

= 2(4x(x-2)+3(x-2))

= 2(4x+3)(x-2)

Width = 2(4x+3)(x-2)/4x+3

Width = 2(x-2)

Width = 2x-4

<em>Hence the width of the rectangle is 2x-4</em>

8 0
2 years ago
:) PLEASE!!!! HELP! some food while you solve &lt;3
Dominik [7]

Answer:

1/3

Step-by-step explanation:

rise over run. Find two places that land on a line I picked (0,0) and (3,1) then count up one from the first point and over 3 for the second.

6 0
3 years ago
Read 2 more answers
A family wants to build a rectangular garden on one side of a barn. If 600 feet of fencing is available to use, then what is the
vovangra [49]

Answer: (A) A=300l-l^{2}

               (B) Length varies between 1 and 150

               (C) Largest area is 22500ft²

Step-by-step explanation: Suppose length is l and width is w.

The rectangular garden has perimeter of 600ft, which is mathematically represented as

2l+2w=600

Area of a rectangle is calculated as

A=lw

Now, we have a system of equations:

2l+2w=600

A=lw

Isolate w, so we have l:

2w=600-2l

w = 300 - l

Substitute in the area equation:

A = l(300 - l)

A = 300l - l²

(A) <u>Function of area in terms of length is given by </u><u>A = 300l - l²</u>

(B) The practical domain for this function is values between 1 and 150.

(C) For the largest area, we need to determine the largest garden possible. For that, we take first derivative of the function:

A' = 300 - 2l

Find the values of l when A'=0:

300 - 2l = 0

2l = 300

l = 150

Replace l in the equation:

w = 300 - 150

w = 150

Now, calculate the largest area:

A = 150*150

A = 22500

<u>The largest area the fence can enclose is </u><u>22500ft².</u>

4 0
2 years ago
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