Question

Factor the trinomial completely. 2x^4 -20x^2+ 32

Answer 1

Answer:

2(x² - 2)(x² - 8)

Step-by-step explanation:

Given

2$x^{4}$ - 20x² + 32 ← factor out 2 from each term

= 2($x^{4}$ - 10x² + 32)

let u = x², then

$x^{4}$ - 10x² + 32 = u² - 10u + 32 = (u - 2)(u - 8)

change u back to x²

$x^{4}$ - 10x² + 32 = (x² - 2)(x² - 8) and

2$x^{4}$ - 20x² + 32 = 2(x² - 2)(x² - 8) ← in factored form