All categories

3 years ago

the length of a rectangle is 5 less than 3 times the width. the perimeter is 150 centimeters. what is the length and width?

1 answer:

3 0

The lenght: x
The width: y
x = 3y-5 (cm)
x + y = 150/2 = 75 (cm)
=> 3y-5+y = 75
=> 4y = 80
=> y = 20 (cm)
=> x = 3×20-5 = 55 (cm)

You might be interested in

Help easy math question!!!

bogdanovich [222]

Answer:

The length of the third side of the triangle is 30.

Step-by-step explanation:

Here is the formula for the Pythagorean Theorem:

$a^{2} + b^{2} = c^{2}$

The hypotenuse, based on the problem, is 50. Anyways, let's get back to calculating!

We need to multiply 40 times 40 and 50 times 50.

40 times 40, or 40 squared, equals to 1600.

50 times 50, or 50 squared, equals to 2500.

$c^{2} - b^{2} = a^{2}$

Now, let's subtract. 2500 - 1600 = 900. We need to find the square root of 900--which is 30, because 30 times 30, or 30 squared, equals to 900.

8 0

3 years ago

An initial deposit of $5,000 is made into a savings account that compounds 3% interest annually. How much is in the account at t

loris [4]

Find how much 3% of $5000 is. Then multiply the 3% by five and add it to 5000. I hope that didn’t sound confusing.

8 0

3 years ago

Read 2 more answers

Please help 20 points!!

frutty [35]

Where is the question?

7 0

3 years ago

Read 2 more answers

The perimeter of a regular 6 -sided figure is 30 units, and the length of each side is x + 1 units.

iren [92.7K]

Answer:

x = 4

Step-by-step explanation:

since each side is equal to x + 1 and there are 6 sides, to get x alone, you have to subtract 1, six times from the perimeter.

1 × 6 = 6

30 - 6 = 24

then divide that by the number of sides (6)

24 ÷ 6 = 4

x = 4!

4 0

3 years ago

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago