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Alex
3 years ago
7

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a blue ma

rble, not replacing it, and picking a brown marble?
Mathematics
2 answers:
Nikitich [7]3 years ago
5 0
There are a total of 19 marbles. 

The chance of picking a blue marble is \frac{7}{19}

Since you didn't put that marble back in, there are 18 marbles still in the bag.

The chance of picking a brown marble is <span>\frac{1}{18}

Multiplying the two values together results with </span>\frac{7}{342}
Alik [6]3 years ago
3 0
The probability of picking a blue marble and not replacing it is 7 out of 19

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lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
5x^2+20=30 please show all work
mezya [45]
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8 0
4 years ago
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Four, five and nine……
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2 years ago
Which pair of triangles can be proven congruent by the HL theorem? 2 right triangles have congruent hypotenuses. 2 triangles hav
lidiya [134]

Answer:

B. If the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of another right triangle, the triangles are congruent.

Step-by-step explanation:

The definition of Hypotenuse-Leg Theorem is stated in option B . In the picture attached, an example is given.

9 0
3 years ago
Read 2 more answers
What does 1 2/5 -3/8 equals to
fgiga [73]
8*5=40

2/5= 16/40

3/8= 15/40

1 16/40-15/40= 1 1/40

1 1/40 is the final answer. 

I hope this helps!
~kaikers
5 0
3 years ago
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