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Alex
3 years ago
7

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a blue ma

rble, not replacing it, and picking a brown marble?
Mathematics
2 answers:
Nikitich [7]3 years ago
5 0
There are a total of 19 marbles. 

The chance of picking a blue marble is \frac{7}{19}

Since you didn't put that marble back in, there are 18 marbles still in the bag.

The chance of picking a brown marble is <span>\frac{1}{18}

Multiplying the two values together results with </span>\frac{7}{342}
Alik [6]3 years ago
3 0
The probability of picking a blue marble and not replacing it is 7 out of 19

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<h3>Solution:</h3>

General Rule for Equation Solving

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Given two consecutive numbers , (n - 1) , n

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multiplying :

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by adding two numbers :

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What is the solution to the system of equations? Use the substitution method.
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Refine:

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Answer A

hope this helps! 
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