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serg [7]
3 years ago
6

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

uthwest Air had the best rate with 80 % of its flights arriving on time. A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.
(a) Find the probability that at least 13 flights arrive late .
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

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Michael rotates ABC to form the image A'B'C'. The table shows the corresponding vertices for ABC and AA'B'C'. What degree of rot
babunello [35]

Answer:

90 degree rotation in the clockwise direction.

Step-by-step explanation:

Point A transforms to A'

- that is x coordinate: 2 ---> 3

and y coordinate   3 ---> -2

So the rotation is clockwise from Quadrant1 to Quadrant 4.

The slope of OA = 3/2 and the slope of OA' = -2/3.

The product of these slopes = 3/2 * -2/3 = -1 so the lines are perpendicular - that is the line has passed through an angle of 90 degrees.

A similar result occurs if we consider points B, C and D.

3 0
3 years ago
A random sample of 5120 permanent dwellings on an entire reservation showed that 1627 were traditional hogans.
krek1111 [17]

Answer:

a) \hat p=\frac{1627}{5120}=0.3178

b)The 99% confidence interval would be given by (0.301;0.355)

Step-by-step explanation:

1) Notation and definitions

X=1627 number of permanent dwellings on the entire reservation that are traditional hogans.

n=5120 random sample taken

\hat p=\frac{1627}{5120}=0.318 estimated proportion of permanent dwellings on the entire reservation that are traditional hogans.

p true population proportion of permanent dwellings on the entire reservation that are traditional hogans.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Part a

The point of estimate for p=the proportion of all permanent dwellings on the entire reservation that are traditional hogans is given by:

\hat p=\frac{1627}{5120}=0.3178

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.318 - 2.58\sqrt{\frac{0.318(1-0.318)}{5120}}=0.301

0.318 + 2.58\sqrt{\frac{0.318(1-0.318)}{5120}}=0.335

The 99% confidence interval would be given by (0.301;0.355)

8 0
3 years ago
a recipe for making 4 cups of soup requires 3 cups of water at this rate how many cups of water are required to make 24 cups of
Tema [17]

Answer:

18

Step-by-step explanation:

4 divided by 24 is 6

6x3=18

8 0
3 years ago
3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is
Margaret [11]
Let p = weight of papaya and g = weight of grapes.

Then (3/4)g = (3/5)p.  Since the weight of grapes is x + 28, 

(3/4)(x + 28) = (3/5)p.  We must solve for x.  To do this, mult. both sides by (5/3):

(5/3)(3/4)(x+28) = (5/3)(3/5)p

Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).


4 0
2 years ago
Luke buys shares for £15.26 each they decrease in value by 3.5% work out the new share price
Murljashka [212]

Answer:

New price is $14.73 Per share

Step-by-step explanation:

(1 - 3.5%) × 15.26 = 14.7259

Round to the nearest hundreth

New share price = $14.73

6 0
1 year ago
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