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serg [7]
3 years ago
6

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

uthwest Air had the best rate with 80 % of its flights arriving on time. A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.
(a) Find the probability that at least 13 flights arrive late .
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

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GREYUIT [131]
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4 0
3 years ago
If 3, x, y, -9 are in A.P, find the values of x and y.​
Serggg [28]

Answer:

  • x = -1
  • y = -5

Step-by-step explanation:

The common difference (d) can be found using the first and 4th terms:

  a1 = 3

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  -9 = 3 +3d . . . . . simplify

  -3 = 1 + d . . . . . . divide by 3

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6 0
3 years ago
PLEASE ANSWER ASAP! MUST BE CORRECT! MORE POINTS GIVEN!!!
Tasya [4]
These are the two rules for when a and b are positive numbers.
a + b = b + a
a - b ≠ b -a
a - b = -b + a

For example:

5.71 + 2.84 = 2.84 + 5.71
8.55 = 8.55

5.71 - 2.84 ≠ 2.84 - 5.71
2.87 ≠ -2.87

5.71 - 2.84 = -2.84 + 5.71
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These are the rules for when a and b are negative numbers.
a + b = b + a
a - b = b + a

For example,

-6.2 + (-3.96) = -3.96 + (-6.2)
-6.2 - 3.96 = -3.96 - 6.2
-10.16 = -10.16

-6.2 - (3.96) = -3.96 + (-6.2)
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Also, if a is a positive number, while b is a negative number, we see these rules:
a + b = a - b
a - b = a + b

For example,

5.71 + (-6.2) = 5.71 - 6.2
-0.49 = -0.49

5.71 - (-6.2) = 5.71 + 6.2
11.91 = 11.91


Also, if a is a negative number while b is a positive number, then these rules will apply:
a + b = b - a
a - b = -b - a

For example,

-3.96 + 2.84 = 2.84 - 3.96
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</span>
-3.96 - 2.84 = -2.84 - 3.96
-6.8 = -6.8


I hope this helps! :)
4 0
3 years ago
Willy Wonka has 2 candies, Wonka bars and Everlasting Gobstoppers. Both have both natural sugar and sucrose in them. Each Wonka
love history [14]

Answer:

Wonka bars=3 and  Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

 4x+2y=60

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-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

1.3(3)+3.2(24)=P

3.9+76.8=P

80.7=P

P=$80.9

8 0
3 years ago
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