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salantis [7]
3 years ago
7

The perimeter of a regular 6 -sided figure is 30 units, and the length of each side is x + 1 units.

Mathematics
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

x = 4

Step-by-step explanation:

since each side is equal to x + 1 and there are 6 sides, to get x alone, you have to subtract 1, six times from the perimeter.

1 × 6 = 6

30 - 6 = 24

then divide that by the number of sides (6)

24 ÷ 6 = 4

x = 4!

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This monitor has a diagonal length of 19 inches and an aspect ratio of 5:4. What are the width and height of the monitor? Round
nasty-shy [4]

<em>Rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>

<h2>Explanation:</h2><h2 />

The aspect ratio is defined as:

<em>"The proportional relationship between the width and height of an image"</em>

It is usually expressed in a mathematical language as:

x:y \\ \\ x: \ Width \\ \\ y: \ Height

So, it is true that:

x:y=5:4 \\ \\ or: \\ \\ \frac{x}{y}=\frac{5}{4} \\ \\ \therefore x=\frac{5y}{4}

In this case, we know that the monitor has a diagonal length (D):

D=19in

So, by Pythagorean theorem:

D^2=361 \\ \\ 361=x^2+y^2 \\ \\ Since \ x=\frac{5y}{4}

D^2=361 \\ \\ 361=x^2+y^2 \\ \\ Since \ x=\frac{5y}{4} \\ \\ 361=\left(\frac{5y}{4}\right)^2+y^2 \\ \\ 361=\frac{25y^2}{16}+y^2 \\ \\ \frac{41}{16}y^2=361 \\ \\ y^2=\frac{261\times 16}{41} \\ \\ y=\sqrt{140.87} \\ \\ y=11.869in

Finding x:

x=\frac{5(11.869)}{4} \\ \\ x=14.836in

<em>Finally, rounded to the nearest tenth of an inch the Witdth of the monitor is 14.8 inches while the Height of the monitor is 11.9 inches.</em>

<h2>Learn more:</h2>

Pythagorean Theorem: brainly.com/question/10182890

#LearnWithBrainly

5 0
3 years ago
What’s
Vadim26 [7]

1.  1.8

2.  100

3.  103.1

4.  16

5. 281.1

6. 27.8

4 0
3 years ago
A lab is trying to determine if a new medication is effective at reducing acne breakouts. The results are displayed in the Venn
In-s [12.5K]

Answer:

its %60 i just took the test and got it right

Step-by-step explanation:

7 0
3 years ago
What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?
iren2701 [21]

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

 triangles

- The slant height of it = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}, where

  b is the length of its base and h is the perpendicular height

- Its lateral area = \frac{1}{2}.p.l, p is the perimeter of the base

 and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}

∴ l = The slant height of it = \sqrt{(\frac{1}{2}.24)^{2}+5^{2}}

∴ l = \sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = \frac{1}{2}.p.l

∴ The lateral area = \frac{1}{2}.(96).(13)

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

4 0
3 years ago
Find the value of x and y is (3x_6) (12,y-1)​
Alika [10]

Answer:

x=4

y=7

Step-by-step explanation:

12=3x

x=4

6=y-1

y=6+1

y=7

8 0
3 years ago
Read 2 more answers
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