59 is an outlier it's not in the 70s
PART - A : tent - 1 volume = 400 cubic ft
Tent -2 volume = 384 cubic ft.
PART - B : I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume
<u>Step-by-step explanation:</u>
PART - A:
tent 1 :
Base = 10 x 10ft
Height= 12 ft
Volume = (1/3) (10x 10) (12)
= (1/3) (100) (12)
= 400 cubic ft.
Tent 2:
Base = 12 x 12 ft
Height= 8 ft.
Volume = (1/3) (12 x 12) (8)
= 384 cubic ft.
PART - B:
I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume
0 = f(x) = (x - r)(x - s) = x² - (r+s) + rs
We have r=1.5+√2, s=1.5 -√2 so r+s = 3 and
rs = (1.5+√2)(1.5 - √2) = 1.5² - (√2)² = 2.25 - 2 = 0.25
f(x) = x² - 3x + -.25
For integer coefficients we mulitply by 4,
g(x) = 4f(x) = 4x² - 12x - 1
Answer: 4x² - 12x - 1 = 0
Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer: {x = 4 {y = 1
Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.
Answer:
4
Step-by-step explanation: