All categories

3 years ago

How do you write 9,000,000+200,000+1,000+500+2 in standard form

Mathematics

2 answers:

Basile [38]3 years ago

8 0

9,201,502 I just added

maks197457 [2]3 years ago

4 0

You write it like this...9,201,502... hope this helps

You might be interested in

suppose the probality that it will rain tomorrow is 0.59. what is the probality that it will not rain tomorrow

kykrilka [37]

Answer: 0.41

Step-by-step explanation: 0.59 is 59%. To find the percentage of chance that it will not rain, you subtract 1 (which is 100%) minus 0.59. You get an answer of 0.41 (or 41% if you prefer.)

7 0

3 years ago

Can someone please help me with this? ^^"

meriva

Answer:

Not issue discussed plz full page

7 0

3 years ago

Help pleaseeee!!! i’ll give brainly

Aloiza [94]

1,13
2,26
3,39
4,52
5,65

6 0

2 years ago

1. (08.01 MC)<br> The graph shows two lines. A and B

Ivahew [28]

Answer:

Part A:

A pair of linear equations can only have one solution or infinitely many solutions. In this case, there would only be one solution as they intersection at only one point.

Part B:

The solution would be (3, 4) because it is the point of intersection between the two linear lines.

6 0

1 year ago

A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only

Semenov [28]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: Number of people that support the candidate.

You need to calculate the sample size to estimate the population proportion of supporters given a confidence level of 99% and a margin of error of 4%

The margin of error of the confidence level for the population proportion is

d= $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

From this formula you have to clear the value of n:

$\frac{d}{Z_{1-\alpha /2}}$ = $\sqrt{\frac{p'(1-p')}{n} }$

$(\frac{d}{Z_{1-\alpha /2}})^2$ = $\frac{p'(1-p')}{n}$

$n*(\frac{d}{Z_{1-\alpha /2}})^2$ = $p'(1-p')$

n= $p'(1-p') * (\frac{Z_{1-\alpha/2}}{d} )^2$

$Z_{1-\alpha/2}= Z_{0.995}= 2.586$

sample proportion "p'" since there is no sample information, nor any previous information is known, you have to consider it as the "worse case scenario" and use the value of p'= 0.50

d= 0.04

$n= p'(1-p') * (\frac{Z_{1-\alpha/2}}{d} )^2= 0.5*0.5*(\frac{2.586}{0.04} )^2= 1044.9= 1045$

She has to take a sample of 1045 people to estimate the population proportion of her supporters with a confidence level of 99% and a margin of error of 4%

I hope this helps!

4 0

2 years ago