Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
Answer:
1) Add 3n to both sides
2) Subtract 5 from both sides
3) Divide both sides by 6
n=3
Step-by-step explanation:
3n+5=23-3n
+3n +3n
6n+5=23
-5 -5
6n=18
/6 /6
n=3
The value of x is 
Explanation:
The expression is
Adding
to both sides of the equation, we get,

Using log definition, if
then
, we have,

Using exponent rule,
,

Simplifying, we have,

Dividing both sides by 9, we have,

Simplifying,

Thus, the value of x is 